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yulyashka [42]
3 years ago
13

pin Co. has $52,000 in its Cash account, $20,000 in its Inventory account, and $12,000 in its Notes Payable (short-term) account

. If Spin’s only other account is Common Stock, what is the balance of that account?
Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

60000

Step-by-step explanation:

Assets - liabilities = share holder equity

(52,000+20,000)−12,000=60000

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2/3 divide by 2/5<br><br> help please
suter [353]

Answer: 1 /3

Explantion:

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2 years ago
Which is the best interpretation of the solution set for the compound inequality?
saw5 [17]

For this case we must find the solution set of the given inequalities:

Inequality 1:

3 (2x + 1)> 21

Applying distributive property on the left side of inequality:

6x + 3> 21

Subtracting 3 from both sides of the inequality:

6x> 21-3\\6x> 18

Dividing by 6 on both sides of the inequality:

x> \frac {18} {6}\\x> 3

Thus, the solution is given by all the values of "x" greater than 3.

Inequality 2:

4x + 3

Subtracting 3x from both sides of the inequality:

4x-3x + 3

Subtracting 3 from both sides of the inequality:

x

Thus, the solution is given by all values of x less than 4.

The solution set is given by the union of the two solutions, that is, all real numbers.

Answer:

All real numbers

8 0
3 years ago
A smaller square is located inside a larger square. the length of the smaller square is 7 cm, and the length of the square is 12
patriot [66]
Let S=larger square side and s=smaller square side.  The area between the larger and smaller is simple the larger area minus the smaller area.  The area of any square being s^2.  So our remaining area is:

A=S^2-s^2

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7 0
3 years ago
Which equation(s) represents proportional relationship(s) with a constant of proportionality equal to 2?
In-s [12.5K]

Answer:

y=2x

Step-by-step explanation:

6 0
2 years ago
Use​ l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove
steposvetlana [31]

Answer:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}

Step-by-step explanation:

The limit is:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}

by replacing, and applying repeatedly you obtain:

\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}

hence, the limit of the function is -1/14

8 0
3 years ago
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