First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
-23/10 or-2 3/10
Step-by-step explanation:
Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is
1
number to the right of the decimal point, place the decimal number over
10
1
(
10
)
. Next, add the whole number to the left of the decimal.
−
2
3
10
From the description, you can get two equation that looks like this:
L= 2*W+6.7cm
Perimeter= 57.2cm
Using perimeter formula, you can put the first and second equation like this:
perimeter= 2L + 2W
57.2cm= 2(2*W+ 6.7)+2W
57.2cm= 4W+ 13.4+ 2W
57.2- 13.4= 6W
W= 43.8/6= 7.3 cm
L= 2W+ 6.7
L= 2*7.3 + 6.7= 21.3
Answer: <span>A. Length=21.3 cm; width=7.3 cm</span>
