The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to
SE = sqrt(p*q/n) where p is the population proportion q is 1-p, and n is the sample size.
<span>(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.) </span>
The margin of error will be Zc*SE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error.
For a 90% confidence interval, Zc is 1.645.
<span>So the margin of error is 1.645 * sqrt(.9*.1/400), roughly .025. So your confidence interval would be around [.875, .925]
The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
Answer:
A
Step-by-step explanation:
<em>Okay so, im not the best at explaining, but so we have a percentage. its 25%. you want to take the 25% and put it over 100 because a percentage is a number or ratio expressed as a fraction of 100. so it will be written as 25%/100</em>
<em />
<em>divide 25 by 100 and you get 0.25, correct? so that's one step further towards the answer.</em>
<em>then we write x/90 because we don't know (well we do) what we're gonna put. but, we're gonna multiply 0.25 by 90 and we get 22.5, which is equivalent to </em><em>22.50</em><em>.</em>
M1 = m4 = 50 (A) is the answer
Answer:
21cm
Step-by-step explanation:
<em>Solution,</em>
<em>Length of fish=40mm=40/10=4cm</em>
<em>Length of pig=25cm</em>
<em>Now, </em>
<em>Difference of their length=25cm-4cm=21cm</em>
<em />
<em>Hence,the pig is 21cm long than the fish</em>
Do you remember the answer..? I need help as well.
