If acr AC is one fifth of the whole circle, angle AOC is 1/5 of 360,
angle ABC is half of angle AOC, so the m∠ABC=36
The surface area is the sum of the area of the six sides...
A=2(xy+xz+yz)
A=2(8*3+8*5+3*5)
A=2(24+40+15)
A=2(79)
A=158 cm^2
Answer:
It’s D
Step-by-step explanation:
So we need to find the two lines...y=mx+b where m is the slope and b is the y-intercept.
m=(dy/dx)=(7-6)/(3-1)=1/2 so
y=x/2+b, now I'll use (1,6) to solve for b
6=1/2+b, b=5 1/2=11/2 so
y1=(x+11)/2
now the other line...
m=(8-6)/(5-3)=2/2=1
y2=x+b, using point (3,6) we solve for b
6=3+b, b=3 so
y2=x+3
Since this is just two lines they will only intersect at a single point and when they do, y=y so we can say:
x+3=(x+11)/2
2x+6=x+11
x+6=11
x=5, now use either line to solve for the corresponding y value...
y2=x+3 becomes y=5+3=8 so the solution to this system is the point:
(5,8)