All categories

2 years ago

PLZ help!!

Mathematics

1 answer:

Paladinen [302]2 years ago

5 0

Answer:

Step-by-step explanation:

At the self employed store, her monthly expense would be

y = $835

Which would plot as a horizontal line

At the franchise store here expense would be

y = 5x where x is the number of haircuts completed.

This would plot as a straight line of slope 5

The two would intersect when the two y values are equal

5 x = 835

so the same cost per month would occur at y = 835

at the franchise, she would have completed 835/5 = 167 haircuts.

If she plans on doing fewer than 167 haircuts per month, she nets more money at the franchise,

If she completes more than 167 haircuts per month, the self employed store deal keeps more money in her pocket.

You might be interested in

WOT IS 10x^2 x 2

Greeley [361]

I think the answer is 20x^2

8 0

3 years ago

Read 2 more answers

The angle measures of a triangle are shown in the diagram.

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Question 3

hoa [83]

answer is (-7,2)

y = -x -5

y= x+9

Both equations have y on the left hand side

So we equate both equations

We replace -x-5 for y in the second equation

-x -5 = x+9

Subtract x on both sides

-2x -5 = 9

Now add 5 on both sides

-2x = 14

Divide by -2 from both sides

x = -7

Now plug in -7 for x in the first equation

y = -x -5

y = -(-7) -5= 7-5 = 2

So answer is (-7,2)

4 0

3 years ago

Read 2 more answers

nine people are to be distributed among three committees of two, three, four members and a chairperson is to be selected for eac

Sonja [21]

b is the answer to your promblem

8 0

3 years ago

Graph the circle (x+6)^2 + (y+5)^2 =9

Andrei [34K]

Answer:

This a circle centered at the point $(-6,-5)$ , and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point $(x_0,y_0)$ is given by:

$(x-x_0)^2+(y-y_0)^2=R^2$

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1) $R^2 = 9\,\,\,then\,\,\,R=3$ since the radius must be a positive number and ( $R=-3$ ) is not a viable answer.

2) $x_0=-6$ for ( $x-x_0$ ) to equal $(x+6)$

3) $y_0=-5$ for ( $y-y_0$ ) to equal $(y+5)$

Therefore, we are in the presence of a circle centered at the point $(-6,-5)$ , and of radius "3". That is what we draw as seen in the attached image.

5 0

3 years ago