3 years ago

Please simplify I need this quick

Mathematics

1 answer:

8_murik_8 [283]3 years ago

8 0

Answer:

$\frac{64x^2}{75y^3}$

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Two planes A and B start from the same place and move in different directions making an angle of 50° between them the speed of p

Alika [10]

Answer:

The distance between them is 230.65 miles

Step-by-step explanation:

Here we use the Cosine formula

$a^2 = b^2 + c^2 - 2bc\ cos\ A\\\\a^2 = 200^2 + 300^2 - 2\times 200\times 300cos50^{\circ}\\\\= 40,000 + 90,000 - 120,000cos50^{\circ}\\\\= 130,000 - 120,000 \times 0.64\\\\= 130,000 - 76,800\\\\a^2= 53,200\\\\a = \sqrt{53,200} \\\\= 230.65\ miles\ per\ hour$

Now the distance for one hour is

= 230.65 ÷ 1

= 230.65 miles

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3 years ago

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Step-by-step explanation:

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2 years ago

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In the coordinate plane, the directed line segment from K to N has endpoints at K(–6, –2) and N(8, 3). Point L partitions the di

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2 years ago

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Two paths in a park intersect so that one of the angles at the intersection is 75°.What are the three other angle measurements f

oksian1 [2.3K]

Answer:

105°, 75°, and 105°.

Step-by-step explanation:

If two straight paths intersect at a point , four angles will be formed.

These are pairs of vertical angles.

The adjacent angles add up to 180°

If one of the angles is 75°, the supplement will be

$180 - 75 = 105 \degree$

Therefore the three other angles will be , 105°, 75°, and 105°.

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2 years ago

The measures of the angles between the resultant and two applied forces are 26° and

erma4kov [3.2K]

Answer:

48.8 lbs

Step-by-step explanation:

The forces can be modeled by a triangle with acute angles 20° and 26°, and obtuse angle 134° opposite a side of length 80. The larger component force will be opposite the angle 26°, and can be found using the Law of Sines:

a/sin(A) = c/sin(C)

x/sin(26°) = 80/sin(134°)

x = 80sin(26°)/sin(134°) ≈ 48.753 . . . . pounds

The larger component force is about 48.8 pounds.

6 0

1 year ago