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4 years ago

Please simplify I need this quick

Mathematics

1 answer:

8_murik_8 [283]4 years ago

8 0

Answer:

$\frac{64x^2}{75y^3}$

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adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago

What is the greatest common factor of 60,90, and 120

garri49 [273]

The answer would be 30.

60/2 = 30
90/2 = 45
120/2 = 60

3 0

3 years ago

Read 2 more answers

How do i turn -24/5 into a decimal answers plz thxs :)

kow [346]

Answer:

-4.8

Step-by-step explanation:

-24/5 = (-24) $\div$ 5

= -4.8

7 0

3 years ago

Read 2 more answers

The circumference of a circle is 20 meters.What is the area

Alex

Answer: the area is 80

Step-by-step explanation:

7 0

3 years ago

Find the area of the shape?

Dominik [7]

Answer:

12π ≈ 37.7

Step-by-step explanation:

A = π*r² - π*r²/4

A = 3πr²/4

r = 4

A = 3π(4)²/4

A = 12π ≈ 37.7

7 0

3 years ago