Given:
Two endpoints of a diameter of a circle:
P (-7, -10)
Q (3, 2)
a) To find the center of the circle, find the midpoint of the two points:
midpoint:
(x2 - x1 )/ 2 , (y2 - y1) / 2
x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5
Therefore, the center of the circle is at C(4.5, 6.5)
b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.
d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2
Answer:
Wsp
Step-by-step explanation:
Answer:
Step-by-step explanation:
y = 3x - 5
y = 1/3x + 3
3x - 5 = 1/3x + 3....multiply everything by 3 to get rid of the fraction
9x - 15 = x + 9
9x - x = 9 + 15
8x = 24
x = 24/8
x = 3
y = 3x - 5
y = 3(3) - 5
y = 9 - 5
y = 4
solution is : x = 3 and y = 4...or (3,4) <==
Si tu prend un chien de 12k je crois que ta réponse va donner 15000
Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)
