1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sidana [21]
3 years ago
13

If h (x) = 1 - 2/3, find h (x) when x is -6.

Mathematics
2 answers:
ruslelena [56]3 years ago
5 0
The answer is h=19/3 :))
Anton [14]3 years ago
3 0

Answer:

h = 19/3

Step-by-step explanation:

You might be interested in
It cost Jocelyn $5.60 to send 56 text messages. How much would it cost to send 198
victus00 [196]

Answer:

$19.8

Step-by-step explanation:

To find the answer, find the  ratio.

7 0
3 years ago
Read 2 more answers
You have some money in your wallet. You don't know the exact amount, but you think you have 60 dollars give or take 15 dollars.
Karolina [17]

Answer:

The least amount is 75 dollars.

The biggest amount is 125 dollars

Step-by-step explanation:

The absolute value function will help us determine a  range of possible values since we do not know the exact amount of money.

Defining the function.

Let x be the exact amount of money in my pocket, we can define the equation

And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation.  So we can write:

We have a difference inside an absolute value, since we know the difference must be either +25 or -25.

Solving for x

Using the definition of absolute value we have

So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is

Solving for x give us

If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition

Solving for x give us

So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.

6 0
2 years ago
You are interested in the relationship between leisure activities and mood. One group of participants watches at least 2 hours o
Romashka [77]

Answer:

The most appropriate statistical test to use to compare the mood scores from the different groups is independent sample t-test.

Step-by-step explanation:

The Independent Samples t-test examines the means of two independent groups to see if statistical evidence exists to show that the related population means differ significantly.

The Independent Samples t-test is also known as Independent t-test, Independent Two-sample t-test, and among others.

It should be note that only two (and only two) groups can be compared using the Independent Samples t-test. It is not possible to use it to make comparisons between more than two groups.

Therefore, the most appropriate statistical test to use to compare the mood scores from the different groups is independent sample t-test.

3 0
3 years ago
What is the answer to 3/4 divided by 2 and 1/2 as a fraction ​
kramer

Answer:

3/10

Step-by-step explanation:

4 0
3 years ago
Class A has 25 pupils and class B has 28 pupils.
postnew [5]

Answer:

I think it will be less than 69 because the tozal mean is 41 while of A is 69 mean the values has decreased

3 0
2 years ago
Other questions:
  • Find the circumference of the circle? D=6ft
    15·2 answers
  • Alex lost 36 pounds in 8 weeks on his new weight loss plan. What was his average change in weight per week?
    12·2 answers
  • Which number is irrational?<br> 16.5%<br> 0.0675<br> 8 3/4<br> 3.14
    8·1 answer
  • Help meeeeee plzzzzzzzzzzz
    9·2 answers
  • Ming throws a stone off a bridge into a river below.
    9·2 answers
  • This is a hard problem
    15·2 answers
  • ASAP!!!!!!!!!!!!!!!!!!!
    15·2 answers
  • Please help I'm dying ​
    8·1 answer
  • 1) work out the size of angle x <br><br> 2) give reasons for your answer
    12·1 answer
  • What must be added to both sides of the equation x – 12 = 15 to isolate the variable?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!