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Yuki888 [10]
2 years ago
11

A) 37 b) 49 c) 46 d) 44

Mathematics
1 answer:
Anni [7]2 years ago
6 0
I’m not sure but is it C? I’m so sorry if it’s wrong
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Which values are solutions to the any quality below <br> check all that apply
Yuri [45]

Answer:

B, C, E, F

Step-by-step explanation:

x^2 >= 49

A. 6: 6^2 = 36 No

B. 20: 20^2 = 400 Yes

C. -7: (-7)^2 = 49 Yes

D. -5: (-5)^2 = 25 No

E. -16: (-16)^2 = 256 Yes

F. 7: 7^2 = 49 Yes

3 0
3 years ago
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
Write a reciprocal function with asymptotes x=4 and y=-9.
gayaneshka [121]
Attached the solution and work.

5 0
3 years ago
Simplify: <br> (sq root of) a^2 if a&gt;0<br><br> (sq root of) 36x^2 if x≤0
tresset_1 [31]

Answer:


Step-by-step explanation:

1.  (sq root of) a^2 if a>0 => √(a^2) = ±a

2.  (sq root of) 36x^2 if a>0 => ±6x

7 0
3 years ago
Find the center and radius of the circle
abruzzese [7]
How do we answer is there’s no pic??
8 0
2 years ago
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