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Savatey [412]
2 years ago
11

How do you solve, j+2j+3j=-20+-16

Mathematics
1 answer:
Natalija [7]2 years ago
5 0

Answer:

j = -6

Step-by-step explanation:

j + 2j + 3j = -20 + (-16)

6j = -36

j = -6

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loris [4]

It can be helpful to remember that "%" is just a shorthand way to write "/100" (divided by 100, or per 100, or per cent). ("Cent" is often used to refer to 100 or 1/100. A "cent" is 1/100 of a dollar, or 1/100 of an acre, for example. A <em>cent</em>ury is 100 years.)

Make the denominator of your fraction be 100. Multiply numerator and denominator by 20/20.

(2/5)×(20/20) = 40/100 = 40%

You can also get there via decimals.

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Or, you can multiply by 100%.

... (2/5)×(100%) = (200/5)% = 40%

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2 years ago
Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function
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In the Figure below is shown the graph of this function. We have the following function:

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Therefore, the y-intercept is the given by the point:

\boxed{(0,-2)}

From the figure we have three x-intercepts:

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So, the x-intercepts occur when y=0. Thus, proving this:

f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0

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3 years ago
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