Question

Find the coordinates of P so that P partitions segment AB in the part-to-whole ratio of 1 to 3 with A(6, -10) and B(9, -1).

Answer 1

Answer:

Step-by-step explanation:

Use the formulas that allow us to find the point that divides the segment into a ratio which is

$x=\frac{bx_1+ax_2}{a+b}$  and  $y=\frac{by_1+ay_2}{a+b}$ where a is 1 (comes from the ratio) and b is 3 (comes from the ratio as well). Filling in:

$x=\frac{3(9)+1(6)}{1+3}=\frac{27+6}{4}=\frac{33}{4}$ and then y:

$y=\frac{3(-1)+1(-10)}{1+3}=\frac{-3-10}{4}=-\frac{13}{4}$ so the coordinates in question are

$(\frac{33}{4},-\frac{13}{4})$

Answer 2

Answer:

Step-by-step explanation:

the answer would be (7,-7)