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3 years ago

PLZ HELP SOON

1 answer:

7 0

13/8 = 1 5/8

Since 13/8 = 1 5/8, A and B cannot be correct.

5/8 > 1/2

Since 5/8 > 1/2, 13/8 is closer to 2 than to 1. Therefore, the answer is D. closer to 2 than to 1.

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There is a prism with a pentagonal base the height is 8 cm the area of the pentagonal base is 30.5cm what is the volume of the p

astraxan [27]

Answer:

244 cm³

Step-by-step explanation:

Step 1: Given data

Height of the prism with a pentagonal base (h): 8 cm

Area of the pentagonal base (A): 30.5 cm²

Step 2: Calculate the volume of the prism with a pentagonal base

We have a regular pentagonal prism, that is, the 5 sides of the base are equal and we know the area of the base and the height of the prism. We can calculate its volume using the following expression.

V = A × h

V = 30.5 cm² × 8 cm = 244 cm³

6 0

3 years ago

Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

beks73 [17]

You can check that the limit comes in an undefined form:

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}$

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

$\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)$

and

$\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}$

So, we have

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)$

6 0

3 years ago

2. Harry just deposited $1500 into a savings account giving 6% interest compounded quarterly.a) How much will be in the account

Studentka2010 [4]

The formula for compound interest is:

$\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{where,} \\ A=\text{ Final amount} \\ r=\text{ Interest rate} \\ n=\text{ Number of times interest applied per period} \\ t=\text{ Number of time period elapsed} \\ P=\text{ Intial principal balance} \end{gathered}$

Given data:

$\begin{gathered} P=\text{ \$1500} \\ r=6\text{ \%}=0.06 \\ n=4\text{ times (compounded quarterly)} \end{gathered}$

a. After ten years, that is t = 10 years, the amount in the account will be

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times10} \\ A=\text{ }1500(1+0.015)^{40} \\ A=\text{ }1500(1.015)^{40} \\ A=\text{ \$2721.03} \end{gathered}$

b. After twenty years, that is t = 20 years, the amount in the account will be:

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times20} \\ A=1500(1.015)^{4\times20} \\ A=1500(1.015)^{80} \\ A=\text{ \$}4935.99 \end{gathered}$

c. The time it takes for Harry's initial account value to double will be:

$\begin{gathered} A=2\text{ x initial value = 2 }\times\text{ \$1500 = \$3000} \\ 3000=1500(1.015)^{4t} \\ (1.015)^{4t}=\frac{3000}{1500} \\ (1.015)^{4t}=2 \\ \text{ Find the logarithm of both sides} \\ \ln (1.015)^{4t}=\ln 2 \\ 4t=\frac{\ln 2}{\ln 1.015} \\ 4t=46.56 \\ t=\frac{46.56}{4}=11.64 \end{gathered}$

Therefore, the time it takes Harry's initial account to double is approximately 11 years

8 0

1 year ago

Cual es el valor de x en x4 = -8

nalin [4]

Answer:56

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Sofia jarred 18 liters of jam after 6 days. How many days does Sofia need to spend making jam if she wants to jar 30 liters of j

Novay_Z [31]

Answer:

10 Days

Step-by-step explanation:

First u need to find out how many liters of jam she made every day so you have to do 18 divided by 6 = 3, she made 3 jams each day. The question is asking how much days she needs to make 30 liters of Jam so divided 30 by 3 and u will get your answer which is 10

6 0

4 years ago