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2 years ago

PLZ HELP SOON

1 answer:

7 0

13/8 = 1 5/8

Since 13/8 = 1 5/8, A and B cannot be correct.

5/8 > 1/2

Since 5/8 > 1/2, 13/8 is closer to 2 than to 1. Therefore, the answer is D. closer to 2 than to 1.

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Joe made a scale drawing of the community pool in his town. the pool has a perimeter of 77 meters, what is the length and width

viva [34]

Answer:

The length of the pool is 28 meters and the width of the pool is 10.5 meters.

Step-by-step explanation:

In the scale drawing of Joe, the community pool has (length : width) = 8 : 3

Let the actual length of the pool is 8x meters and the actual width is 3x meters.

Now, given that the actual pool has a perimeter of 77 meters.

So, 2(8x + 3x) = 77

⇒ 22x = 77

⇒ x = 3.5

So, the length of the pool is 8x = 8(3.5) = 28 meters and the width of the pool is 3x = 3(3.5) = 10.5 meters. (Answer)

8 0

2 years ago

Need help math testt

Serga [27]

Answer:

Step-by-step explanation:

8 0

2 years ago

7 - 3x = 5x + 13. What is x?

eduard

Answer:

x= -3/4 or -0.75

Step-by-step explanation:

1) subtract 7 from both sides which would make it

-3x= 5x+6

2) Subtract 5x from both sides which would make it

-8x-6

3) Divide both sides by -8

which gives you -3/4

7 0

2 years ago

Read 2 more answers

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

$z=\frac{x}{y}$

we have

$x=12\ cm$

$y=9\ cm$

substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

Find the area of the larger figure

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

$z^{2}=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

$x=390*16/9=693.33\ cm^{2}$

4 0

2 years ago

(9y+6)+(y+3) Add. Please help

Levart [38]

(9y+y) + (6+3)
The answer is 10y+9

5 0

2 years ago