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Licemer1 [7]
3 years ago
5

What is the Area of the Trapezoid GHIK?

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

The area of the trapezoid is 56 sq ft

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Please help me, i need the answers ASAP! (With proper steps please)
docker41 [41]

a) 35 x 13 + 3.14 x \frac{13}{2}²

= 455 + 3.14 x 42.25

= 455 + 132.665

= 587.665 m²

∴ The area is  587.665 m².

4 0
2 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
2 years ago
H(x)=4|x+4|+3 what’s the answer
MatroZZZ [7]

Answer:

To find the transformation, compare the two functions and check to see if there is a horizontal or vertical shift, reflection about the x-axis, and if there is a vertical stretch.

Parent Function:

g(x)=|x|

Horizontal Shift: Right 4 Units

Vertical Shift: Up 1 Units

Reflection about the x-axis: None

Vertical Compression or Stretch: None

Step-by-step explanation:

4 0
2 years ago
What is the solution set of x2 + 5x - 5 = 0?
Llana [10]

If you're completing the square the answer is in the image.

expression

x^2 + 5x - 5=ax^2+bx+c

a=1, b=5, c=-5, and you can solve it that way.

4 0
3 years ago
Hey! please help i’ll give brainliest! if it lets me:)
lozanna [386]

Answer:

south since its the opposite

5 0
3 years ago
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