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densk [106]
3 years ago
7

Which domain restrictions apply to the rational expression?

Mathematics
1 answer:
andre [41]3 years ago
4 0

Both expression have the same denominator: 9x²-1. Thus it must not be 0.

9x²-1=(3x-1)(3x+1)=0, resulting x=+-1/3.

Restrictions: x in R\{-1/3, 1/3}

Adding those expressions:

E=(-x-2)/(9x²-1 ) + (-5x+4)/(9x²-1)=

(-x-2-5x+4)/(9x²-1)=(-6x+2)/(9x²-1)=

(-2)(3x-1)/(9x²-1)=-2/(3x+1)

E=-2/(3x+1)

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Harlamova29_29 [7]

Answer:

<h2>          y - 5 = -3(x + 1)</h2>

Step-by-step explanation:

Parallel lines has the same slope.

The equation of a line that passing through point (x₁, y₁) with a slope of m is:

y - y₁ = m(x - x₁)

m = -3

(-1, 5)   ⇒  x₁ = -1,  y₁ = 5

Therefore the equation:

y - 5 = -3(x + 1)

5 0
3 years ago
Write the expression using rational exponents. Then simplify and convert back to radical notation.
ioda

Answer:

The radical notation is 3x\sqrt[3]{y^2z}

Step-by-step explanation:

Given

\sqrt[3]{27 x^{3} y^{2} z}

Step 1 of 1

Write the expression using rational exponents.

\sqrt[n]{a^{m}}=\left(a^{m}\right)^{\frac{1}{n}}

=a^{\frac{m}{n}}:\left({27 x^{3} y^{2} z})^{\frac{1}{3}}

$(a \cdot b)^{r}=a^{r} \cdot b^{r}:(27)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

=$(3^3)^{\frac{1}{3}}\left(x^{3}\right)^{\frac{1}{3}} \cdot\left(y^{2}\right)^{\frac{1}{3}} \cdot(z)^{\frac{1}{3}}$

$=\left(3\right)\left(x}\right)} \cdot\left(y}\right)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

Simplify $3 x \cdot(y)^{\frac{2}{3}} \cdot(z)^{\frac{1}{3}}$

$=3 x \sqrt[3]{y^{2} z}$

Learn more about radical notation, refer :

brainly.com/question/15678734

4 0
3 years ago
How can you use the properties of operations to evaluate<br> this expression?<br> 18 + 4(28)
nirvana33 [79]

Answer:

Well on of the properties states that unless there are parenthesis, you multiply and divide first then you add and subtract. So, first we multiply 28*4 and that leaves use with 112, now if there is no more multiplication, division, or parentheses, and there's not. We can continue all we do is add 18+112 and we get our answer of 130.

6 0
3 years ago
Read 2 more answers
PLEASE HELP!
Igoryamba
Hello! $200 is the fixed amount. B doesn't have 200 as part of the problem, so B is eliminated. A is also out, because you add, not subtract. 100 is the amount of boots made, not the amount made per pair of boots. 100 would be the value of "x". The cost per day is $9,200, and 9,200 - 200 is 9,000. With 100 pairs of boots being made each day, 9,000/100 is 90. It would cost $90 per pair of boots made, with the variable "x" being beside it. The correct equation would be C(x) = 90x + 200. The answer is D.
7 0
3 years ago
Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a
Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person has the disease

<em>P</em> = the test result is positive

<em>N</em> = the test result is negative

Given:

P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10

Compute the value of P (P|X) as follows:

P(P|X)=1-P(P|X^{c})=1-0.15=0.85

Compute the probability of a positive test result as follows:

P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22

Compute the probability of a person having the disease given that he/she was tested positive as follows:

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The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

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