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2 years ago

Help me pls I beg I beg I beg bbg

Mathematics

2 answers:

vivado [14]2 years ago

6 0

Answer:

72.25

Step-by-step explanation:

Triangles are 1/2(base x height), or (base x height) / 2.

17 x 8.5 = 144.5

144.5 / 2 = 72.25

dsp732 years ago

6 0

74.25 square inches.

The formula to find the area of a triangle is A = 1/2(b)(h). (b being base and h being height)

A=1/2(17)(8.5)
A=1/2(144.5)
A= 72.25 :)

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3 coins Priya spends $45 on gas, $10 on dinner, and $8 on a video game. How much money did Priya spend on variable expenses?

NISA [10]

Answer:

3x=63

Step-by-step explanation:

3 coins means a coin is x and total expenditure is equal to 63

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2 years ago

The points (2,-5) and (5,r) lie on a line with slope 2. Find the missing coordinate r.

Andrew [12]

Answer: r = 1

Step-by-step explanation:

The slope of a line can be represented as $\frac{y_2-y_1}{x_2-x_1}$ . Plugging in the following values would provide you with:

$\frac{(r)-(-5)}{(5)-(2)} =2$

$\frac{r + 5}{3} = 2$

$r + 5 = 6$

$r = 1$

Hope it helps :) and let me know if you want me to elaborate on anything.

7 0

2 years ago

Which equation is the inverse of y=100-x2

postnew [5]

Answer:

f^-1(x)=100-x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

jamerra received a $3,00 car loan. she plans on paying off the loan in 2 years. at the end of 2 years, jamerra will have paid $4

leonid [27]

The rate of interest is 75 % per year

Solution:

Given that, Jamerra received a $3,00 car loan

she plans on paying off the loan in 2 years

Jamerra will have paid $450 in interest

Therefore, we get

Principal = $ 300

Number of years = 2

Simple Interest = $ 450

Rate of interest = ?

The simple interest is given by formula:

$simple\ Interest = \frac{p \times n \times r}{100}$

Where,

"p" is the principal and "n" is the number of years and "r" is the rate of Interest

Substituting the given values we get,

$450 = \frac{300 \times 2 \times r}{100}\\\\450 = 3 \times 2 \times r\\\\6r = 450\\\\r = \frac{450}{6}\\\\r = 75$

Thus rate of interest is 75 % per year

5 0

3 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider