<em>Hello There!!</em>
Let us call X the equal distances GH = HI = IJ
GH = X
HI = X
IJ = X
Note that HJ = HI + IJ, so
HJ = X + X
10 = 2X
X = 5
Well, We're looking at figure we can conclude that:
GJ + JK = GK
GJ = GH + HI + IJ
GJ = 15
GJ + JK = GK
15 + JK = 24
JK = 9
GH = X = 5
HI = X = 5
IJ = X = 5
JK = 9
<h3>Given</h3>
... 4 - |2x -1| = -3
<h3>Find</h3>
... x
<h3>Solution</h3>
Add |2x-1|+3
... 7 = |2x-1|
This resolves to two equations:
... -7 = 2x-1
... -6 = 2x
... -3 = x
and ...
... 7 = 2x -1
... 8 = 2x
... 4 = x
The two solutions are x = -3 and x = 4.
Answer:
1) A, C, and D all represent linear equations.
2) A, C, and D are functions; none of them have repeating x values.
3) D
