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dezoksy [38]
2 years ago
9

Please help me with this math

Mathematics
1 answer:
Montano1993 [528]2 years ago
8 0

Answer:

um I don't understand it pls be more specific and I will help

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Which of the following graphs represents the solution set for 7(4x – 1 ) + 6x > –279? PLEASE HELP
Luda [366]
First, solve the inequality:
7(4x - 1 ) + 6x \ \textgreater \  -279\\
28x-7+6x\ \textgreater \ -279\\
34x\ \textgreater \ -272\\
x\ \textgreater \ -8
Since x is <u>greater than</u> -8, you have the arrow point up the graph towards the positive side starting at -8.
Since it's greater than but not equal to -8, the circle is open.

Thus your graph is D.
3 0
3 years ago
Which shows the best estimate to use<br> to find 43 × 78?
Over [174]

Answer:

The best estimate for 43x78 is 40x80

Step-by-step explanation:

43 rounded to the nearest ten is 40.

78 rounded to the nearest ten is 80.  

The answer to 40x80 is 3200

4 0
3 years ago
Which additional word or words in the sentence should be capitalized?
Montano1993 [528]
A, C, and D. Hope this helps!
3 0
3 years ago
Read 2 more answers
3 connecting lines are shown. Line D F is horizontal. Line D E is about half the length of line D F. Line F E is about one-third
mars1129 [50]

The inequality that explains why the three segments cannot be used to construct a triangle is ED + EF < DF

<h3>Inequalities </h3>

From the question, we are to determine which of the given inequalities explains why the three segments cannot be used to construct a triangle

From the given information,

Line DE is about half the length of line DF

That is,

ED = 1/2 DF

Also,

Line FE is about one-third of the length of line DF

That is,

EF = 1/3 DF

Then, we can write that

ED + EF = 1/2DF + 1/3DF

ED + EF = 5/6 DF

Since,

5/6 DF < DF

Then,

ED + EF < DF

Hence, the inequality that explains why the three segments cannot be used to construct a triangle is ED + EF < DF

Learn more on Inequalities here: brainly.com/question/1447311

#SPJ1

5 0
2 years ago
How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

8 0
3 years ago
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