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bogdanovich [222]
3 years ago
8

The measure of an angle is twenty-four times the measure of its complementary angle. What is the measure of each angle?

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

<h2>         3.6° and 86.4°</h2>

Step-by-step explanation:

24x   - measure of an angle

x      - the measure of a complementary angle

Complementary angles adds to 90°

x + 24x = 90°

25x = 90°

x = 90°÷25

x = 3.6°

24x = 24·3.6° = 86.4°

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3 years ago
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An atlas contains a map of Ohio. The table shows data from the key on the map.
Rashid [163]

Answer:

The answer is below

Step-by-step explanation:

a) The graph is attached

b) The table shows a linear relationship between x and y.

A linear equation is in the form y = mx + b, where y is a dependent variable, x is an independent variable, m is the rate of change (slope) and b is the value of y when x = 0.

x represent the distance on map in mm and y represent the actual distance in mile. The table (x, y) has the points (10, 25) and (20, 50). The equation is given by:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-25=\frac{50-25}{20-10} (x-10)\\\\y-25=2.5(x-10)\\\\y-25=2.5x-25\\\\y=2.5x

The slope m = 2.5. This means that for every 1 mm on the map, the actual distance increases by 2.5 miles.

c) y = 2.5x

put x = 48 mm

y = 2.5(48)

y = 120 miles

The actual distance between Toledo and Columbus is 120 miles

d) y = 2.5x

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8 0
3 years ago
This is chain rule please help if u are smart​
Helga [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Sally painted a picture that has an area of 480 square inches. The length of the painting is 1 1/5 its width. Which of the follo
prohojiy [21]
A = 480
W = x
L = 11/5*x
therefore 480 = 11/5*x*x
480 = 11/5x^2
480*5 = 11x^2
2400/11 = x^2
+ or-\sqrt{2400/11} = x
However we can't have a negative width so width is \sqrt{2400/11}
Sub this into the length equation to find length \frac{11}{5} *  \sqrt{2400/11}
5 0
3 years ago
(p÷q)<br><img src="https://tex.z-dn.net/?f=2x%20%2B%202" id="TexFormula1" title="2x + 2" alt="2x + 2" align="absmiddle" class="l
ryzh [129]

Answer:

Step-by-step explanation:

Hello,

\dfrac{p}{q}*\dfrac{q}{p}=1=(2x+2)(2-x)\\\\ 4x-2x^2+4-2x=1\\\\ -2x^2+2x+4-1=0\\\\ -2x^2+2x+3=0\\\\

There are two solutions

\Delta=b^2-4ac=2^2+4*2*3=4+24=28=7*4\\x_1=\dfrac{-2+\sqrt{7*4}}{-4}=\dfrac{-2+2\sqrt{7}}{-4}=\dfrac{1-\sqrt{7}}{2}\\x_2=\dfrac{1+\sqrt{7}}{2}\\

Hope this helps

5 0
3 years ago
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