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lana66690 [7]
3 years ago
8

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

20 square feet

Step-by-step explanation:

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Step 1

We find the Length and Width of the deck

Perimeter of a rectangle = 2L + 2W

The length of a rectangular deck is five times it's width

W = Width

L = Length = 5W

P = 24 feet

Perimeter = 2(5W) + 2W

24 = 10W + 2W

24 = 12 W

W = 24/12

W = 2 feet

Solving for L

L = 5W

L = 5 × 2 feet

L = 10 feet

Step 2

We find the area of the deck

Area of the deck(Rectangle) = Length × Width

= 10 feet × 2 feet

= 20 square feet

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Kim ran total 7.1 miles.

Further explanation:

Front end estimation is the specific technique for rounding off numbers to estimates sums and differences. The numbers to be added or subtracted are rounded off to nearest one, tenth and hundredth.

So in the given scenario, we will round off to the nearest tenth.

So,

2.76 miles will be rounded off to 2.8 as the number right to the digit 7 is greater than 5, 7 will be rounded off to the next digit.

2.34 miles will be rounded off to 2.3 as the number right to 5 is less than 5, so 3 will be as it is.

1.97 miles will be rounded off to 2.0 as the number right to 9 is greater than 5 so it will be rounded off to the next number.

So, after estimation

2.8+2.3+2.0 = 7.1\ miles

Keywords: Front-end estimation, decimals

Learn more about decimal numbers at:

  • brainly.com/question/1677114
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Find the sum of the solutions of this equation 3x2+14x+8=0
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Answer:

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Two methods, A and B, are available for teaching a certain industrial skill. The failure rate is 35\% for A and 15\% for B. Howe
valentina_108 [34]

Answer:

Therefore the probability that he was taught by method A is 0.78.

Explanation:

<h3>Probability:</h3>

The ratio of the number of favorable outcomes to the number of all possible outcomes.

<h3>Bayes' Rule:</h3>

If the events B_1,B_2, .....B_n from a portion of a sample space S and A is any events of A, then

P(B_i|A)=\frac{P(B_i)P(A|B_i)}{\sum_{j=1}^kP(B_j)P(A|B_j)}

Given that,

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The failure rate for A is 35%

That is P(F|A) =35%=0.35

The failure rate for B is 15%

That is P(F|A) =15%=0.15

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B used 60% of the time.

P(A)=60%=0.60

To find P(A|F) , we use the Bayes's rule.

P(A|F)=\frac{P(A)P(F|A)}{P(A)P(F|A)+P(B)P(F|B)}

            =\frac{0.60\times 0.35}{0.60\times 0.35+0.40\times 0.15}

           =0.78

Therefore the probability that he was taught by method A is 0.78.

4 0
4 years ago
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