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3 years ago

I need the answer in the next 6 hours

Mathematics

2 answers:

Vinil7 [7]3 years ago

7 0

Answer:

She is 180m from the information Center

She walked 240m from the parking lot to the lake.

Step-by-step explanation:

I searched your question and found the key answers. below is my backup explanation, hope this helps! brainliest, please!

balandron [24]3 years ago

3 0

Answer:

180m

Step-by-step explanation:

The figure shown in the picture is a right triangle.

We have two of it's sides and need to find the hypotenuse (the side in front of the right angle).

To find that we must use the Pythagorean theorem:

$c^{2} = {a}^{2} + {b}^{2}$

Side a is 400m and side b is 300m.

Therefore:

$c^{2} = {300}^{2} + {400}^{2}$

$c = \sqrt{300 \times 300 + 400 \times 400} = 500$

Now that we know that side c is 500m we must just substract the distance between Marla and the dock with the lenght of the side to find the answer

500 - 320 = 180m

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Use an algebraic approach to solve the problem.

qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 = ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0

3 years ago

PLEASEEE I NEED HELPPP!!!!

taurus [48]

Answer:

#carry on learning

mark me as brainliest

Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)

I really need this question answered

By:

I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).

I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.

The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:

y = 6x + b

We need to find b, so substitute the point (-5,4) that we know is on the line:

4 = 6*(-5) + b and solve for b

4 = -30 + b

b = 34

The line is y = 6x + 34

4 0

3 years ago

How do you solve: 3In5+4Inx

Dafna11 [192]

Answer:

ln(125x $x^{4}$ )