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Vikki [24]
3 years ago
8

Find x (btw if you answer this randomly just to get the point I'm reporting ur acc​

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

3.5 times 2 equals 7 so try 2.5 times 2 which would be 5, 5 could be the answer but im not sure :)

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Just go down the row and say yes no yes no in order!you don't have to type the whole thing out
tangare [24]

Answer:

1) yes

2) no

3) yes

4)no

5)no

Step-by-step explanation:

8 0
3 years ago
What is the difference between a copay and coinsurance?
bearhunter [10]

Answer:

A deductible is the amount you pay for a service before the plan shares the cost of the service with you. A copay is a set amount you pay for the service. Coinsurance is when you pay a percentage of the cost for an item or service.

4 0
3 years ago
5x<br><img src="https://tex.z-dn.net/?f=5x%20%7B%20%7B%20%3D%2045%7D%5E%7B%3F%7D%20%7D%5E%7B2%7D%20" id="TexFormula1" title="5x
Ilia_Sergeevich [38]
\bf 5x=45^2\implies x=\cfrac{45^2}{5}\implies x=\cfrac{2025}{5}\implies x=405
8 0
3 years ago
Write a compound interest function to model each situation. Then find the balance after the given number of years.
Reika [66]

Answer:

hi

Step-by-step explanation:

7 0
3 years ago
Kaden works 5 days. The median number of hours he works is 3. The mean number of hours he works is 4.
alisha [4.7K]

Answer:

(a) 1, 2, 3, 6, 8

Step-by-step explanation:

Given

Median = 3

Mean = 4

Required

The sequence of hours worked each day

<em>See attachment for options</em>

From the question, we understand that:

Median = 3

This means that, the middle number is 3 (when sorted)

So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively

Next, is to determine the mean of (a) and (d)

The mean of a data is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

(a)

\bar x = \frac{1+ 2+ 3+ 6+ 8}{5}

\bar x = \frac{20}{5}

\bar x = 4

(d)

\bar x = \frac{1+ 2+ 3+ 4+ 5}{5}

\bar x = \frac{15}{5}

\bar x = 3

Option (a) is true, because it has:

Median = 3

Mean = 4

7 0
3 years ago
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