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3 years ago

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The coffee merchant plans to mix some fancy $6.50 per pound ground coffee called royal soil with 10 pounds of a lowly $2 per pou

nd ground called royal peasant. How many pounds of the $6.50 per pound ground coffee should he use?

1 answer:

taurus [48]3 years ago

8 0

Answer and explanation:

Given:

Royal soil= $6.50 per pound

Royal peasant = $2 per pound of 10 pounds

Blend total pounds is x+10, price is unknown hence solved below

Using algebra

We find unknown x = number of pounds of royal soil

$6.50(x)+$2(10)=6.50x+20/x+10(x+10)

= 6.50x+20= 6.50x²+85x+200

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Simplify the expression: 2(4 + 6j)

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}$

Step-by-step explanation:

$\sf{2(4 + 6j)}$

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$\longrightarrow{ \sf{2 \times 4 + 2 \times 6j}}$

$\longrightarrow{ \sf{8 + 12j}}$

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3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

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$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

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3 years ago

How do u multiply exponents

Ymorist [56]

So, by multiplying the exponents, you would add all of the square roots together. For example for your question you would add 1+1+4+5=11 so the answer is c to the power of 11

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Answer:

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Answer:

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