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3 years ago

8

A car entering a freeway accelerates from a speed of 15.00 m/s to a speed of 25.00 m/s in a time of 2.50s. What is the accelerat

ion of the car?

1 answer:

san4es73 [151]3 years ago

8 0

the acceleration of the car is 25.00 m/s

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The equation C = 5 9 F − 160 9 gives the relation between temperature readings in Celsius and Fahrenheit.

Pavel [41]

Step-by-step explanation:

The question is wrong. The correct equation is :

$C=\frac{5}{9}F-\frac{160}{9}$

We know that the equation gives the relation between temperature readings in Celsius and Fahrenheit.

Therefore, giving that we know the value in Fahrenheit ''F'' we can find the reading in Celsius ''C''. This define a function C(F) that depends of the variable ''F''.

So for the incise (a) we answer Yes, C is a function of F.

For (b) we need to find the mathematical domain of this function. Giving that we haven't got any mathematical restriction, the mathematical domain of the function are all real numbers.

Dom (C) = ( - ∞ , + ∞)

For (c) we know that the water in liquid state and at normal atmospheric pressure exists between 0 and 100 Celsius.

Therefore the range will be

Rang (C) = (0,100)

Now, we need to find the domain for this range. We do this by equaliting and finding the value for the variable ''F'' :

For C = 0 :

$0=\frac{5}{9}F-\frac{160}{9}$ ⇒ $F=32$

And for C = 100 :

$100=\frac{5}{9}F-\frac{160}{9}$ ⇒ $F=212$

Therefore, the domain as relating temperatures of water in its liquid state is

Dom (C) = (32,212)

For (d) we only need to replace in the equation by $F=71$ and find the value of C ⇒

$C=\frac{5}{9}F-\frac{160}{9}$ ⇒

$C=(\frac{5}{9})(71)-\frac{160}{9}$

$C=\frac{65}{3}$ ≅ 21.67

C(71) = 21.67 °C

4 0

2 years ago

A calculator was used to perform a linear regression on the values in the table. The results are shown to the right of the table

BartSMP [9]

Answer:

the answer is c y=-3.6x+12.8

5 0

2 years ago

If f(x) =3x-5 them find values of f(3) and f(-7). please explain step by step

LenKa [72]

Answer:

f(3) = 4

f(-7) = -26

Step-by-step explanation:

Hi there!

$f(x) =3x-5$

To find f(3), replace every x with 3:

$f(3) =3(3)-5\\f(3) =9-5\\f(3) =4$

Therefore, f(3)=4.

$f(x) =3x-5$

To find f(-7), replace every x with -7:

$f(-7) =3(-7)-5\\f(-7) =-21-5\\f(-7) =-26$

Therefore, f(-7)=-26.

I hope this helps!

8 0

2 years ago

Mr. Daniels is organizing a class trip on a budget of $900. The bus rental costs $600. Mr. Daniels will also buy tickets that co

Mars2501 [29]

Answer:

Mr.Daniels is a fajjett

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The number of kilograms of water in a human body varies directly as the mass of the body. An 87-kg person contains 58 kg of wat

katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form $y=kx$ , where y varies directly with x and k is constant of variation.

We are told that an 87-kg person contains 58 kg of water. We can represent this information in an equation as:

$58=k\cdot 87$

Let us find the constant of variation as:

$\frac{58}{87}=\frac{k\cdot 87}{87}$

$\frac{29*2}{29*3}=k$

$\frac{2}{3}=k$

The equation $y=\frac{2}{3}x$ represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute $x=75$ in our given equation and solve for y.

$y=\frac{2}{3}(75)$

$y=2(25)$

$y=50$

Therefore, there are 50 kg of water in a 75-kg person.

3 0

3 years ago