Answer:
Option C is correct i.e. 2.
Step-by-step explanation:
Given the function is f(x) = x² +8x -2.
We can compare it with general quadratic expression i.e. ax² +bx +c.
Then a = 1, b = 8, c = -2.
We can find the number of real root by finding discriminant of the equation ax² +bx +c =0 as follows:-
D = b² -4ac
D = 8² -4*1*-2
D = 64 +8
D = 72.
When D is a positive value, then we have two real roots of the equation.
Hence, option C is correct i.e. 2.
0.69x+4.32=0.46x+3.4
-3.4 -3.4
____________________
0.69x+0.92=0.46x
-0.69x -0.69x
______________
0.92=-0.23
multiply by -100/23 multiply by -100/23
x=-4
K= -3
3y = x+6 can be rewritten as y = 1/3x + 2
a perpendicular slope is the opposite reciprocal of the original slope
so instead of 1/3 it would be -3
therefore. k must equal -3 to be perpendicular to 3y = x+6
Answer:
<h3>
(2, 124)</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)
![f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-16x%5E2%2B%2064x%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x%5E2-%204x%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28%5Cunderline%20%7Bx%5E2-2%5Ccdot2x%5Ccdot2%2B2%5E2%7D-2%5E2%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%5Cbig%5B%28x-2%29%5E2-4%5Cbig%5D%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x-2%29%5E2%2B64%20%2B%2080%5C%5C%5C%5C%5Cbold%7Bf%28x%29%3D-16%28x-2%29%5E2%2B124%5Cquad%5Cimplies%5Cquad%20h%3D2%5C%2C%2C%5Cquad%20k%3D124%7D)
<u>The vertex is </u><u>(2, 124)</u>
Divide 5.6 by 8 which is 0.7. Since the image of the ant is 8 times bigger we need to divide by 8 to make it actual size.
The ant's actual length is 0.7 cm.
