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luda_lava [24]
2 years ago
6

Helppppppppppppppp!!!!!

Mathematics
1 answer:
marta [7]2 years ago
5 0

Hi there!

\large\boxed{\text{ UVY} = 65^o, \text{ VYZ }= 65^o}

We can begin by finding ∠VUY so we can solve for ∠UVY.

∠VUY is supplementary to ∠TUY, so:

180 = 144 + ∠VUY

∠VUY = 36°

In a triangle, angles sum up to 180°, so:

180 = 36° + 79° + m∠UVY

m∠UVY = 65°

Solve for m∠VYZ by comparing the angle to m∠UVY because the angles are alternating interior angles. Thus:

m∠UVY = m∠VYZ = 65°.

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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
What is the approximate circumference of a circle with a radius of 42.1 km?
harina [27]
C.264.4 that should answer your question

4 0
3 years ago
Read 2 more answers
Which could NOT be the shape of a cross section of this cylinder?
fredd [130]

Answer:

Circle

Step-by-step explanation:

4 0
3 years ago
2) 4 6 2 3 If L= | 5 8 and M= 1 4 3 -2 -5 3 3 Find L-M -)) 2 4 8 A ) 3 4 5 2 3 B) 4 4 8 -5 6 9 o 6 12 -2 1 6 6 2 D) 9 12 1​
Misha Larkins [42]

\\ \sf\longmapsto L-M

  • Put values

\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]

Just substract corresponding terms

\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]

Option B

6 0
3 years ago
One hundred coins weigh 346 grams. How many grams does 1 coin weigh?
Pani-rosa [81]

Answer:

3.46 grams

Step-by-step explanation:

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