Hi there!
We can begin by finding ∠VUY so we can solve for ∠UVY.
∠VUY is supplementary to ∠TUY, so:
180 = 144 + ∠VUY
∠VUY = 36°
In a triangle, angles sum up to 180°, so:
180 = 36° + 79° + m∠UVY
m∠UVY = 65°
Solve for m∠VYZ by comparing the angle to m∠UVY because the angles are alternating interior angles. Thus:
m∠UVY = m∠VYZ = 65°.
Answer:
Y = 32.7°
Step-by-step explanation:
We will apply the Cosine law in the given triangle XYZ,
x = 90 ft
y = 55 ft
z = 50 ft
We have to find the measure of angle Y.
y² = x² + z² - 2xzCosY
(55)² = (90)² + (50)² - 2(90)(50)cosY
3025 = 8100 + 2500 - 9000.cosY
9000.cosY = 10600 - 3025
cosY =
= 0.84167
Y =
Y = 32.68 ≈ 32.7°
Therefore, measure of angle Y = 32.7°
Answer:
Required Probability = 0.1283 .
Step-by-step explanation:
We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.
Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.
Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.
Let X = mean weight of the babies, so X ~ N()
The standard normal z distribution is given by;
Z = ~ N(0,1)
where, X bar = sample mean weight
n = sample size = 4
Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)
P(X bar > 7.5) = P( >
) = P(Z > 1.1428) = 0.1283 (using z% table)
Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .