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Paladinen [302]
3 years ago
9

Solve for y. 9y-9 11 = 8 + 3y-2 2 implify your answer as much as possible ​

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

2y=299

Step-by-step explanation:

:)

You might be interested in
Write 5 and 2/5 as a decimal
Alenkasestr [34]

Answer:

5.4.

Step-by-step explanation:

If we divide 2 by 5 we get 0.4

So 5 and 2/5 = 5.4

7 0
4 years ago
Read 2 more answers
The answer to question 24 please!
erica [24]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
Based on the extreme value theorem, what is the maximum value of f(x) = –x2 + 6x over the interval [1, 4]?
Tju [1.3M]

Answer:

Maximum\ value\ =9 ,at\ x=3

Step-by-step explanation:

From the question we are told that:

Function given

f(x) = -x^2 + 6x

Co-ordinates

(x,y)=[1, 4]

Generally the second differentiation of function is mathematically given by

-2x+6

Therefore critical point

x=3

Generally the substitutions of co-ordinate into function is mathematically given by

For 1

F(1)=-(1)^2 + 6(1)\\F(1)=5

For 4

F(4)=-(4)^2 + 6(4)\\F(4)=8

For critical point 3

F(3)=-(3)^2 + 6(3)\\F(3)=9

Therefore the maximum value of f(x) = –x2 + 6x over the interval [1, 4] is given by

Maximum\ value\ =9 ,at\ x=3

3 0
3 years ago
Read 2 more answers
Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose
Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3.  Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16.  Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.

Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.

5 0
3 years ago
Solve 2x2 – 6x + 10 = 0 by completing the square.
Ugo [173]

Answer:

Step-by-step explanation:

2x^2-6x+10=0

2(x^2-3x)+10=0

2(x-(3/2))^2-9/4)+10=0

2(x-(3/2))^2+10-9/2=0

2(x-(3/2))^2+(20-9)/2=0

2(x-(3/2))^2+11/2=0

2(x-(3/2))^2=-11/2

square is always positive so there is no solution

5 0
3 years ago
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