Helppppp with these two and explain pls and ty <3

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago

Find a unit vector in the direction of the vector left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 8 2nd Row 1st Col

MrRissso [65]

Answer:

$\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]$

Step-by-step explanation:

We are required to find a unit vector in the direction of:

$\left[\begin{array}{c}-8\\7\\2\end{array}\right]$

Unit Vector, $\hat{a}=\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}$

The Modulus of $\overrightarrow{a}$ = $\sqrt{(-8)^2+7^2+(-2)^2}=\sqrt{117}$

Therefore, the unit vector of the matrix is given as:

$\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]$

5 0

3 years ago

The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the

Artyom0805 [142]

Answer:

$500

Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

<u>Second Discount</u>

20% off means we paid 80%. We know we paid $328 of some price.

$\frac{80}{100} =\frac{328}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$80y=100(328)\\80y=32800$

I now solve for y by dividing by 80.

$\frac{80y}{80} =\frac{32800}{80} \\y= $410$

The price after the first discount was $410.

<u>First Discount</u>

We will repeat the steps above with $410. 18% off means we paid 82%.

$\frac{82}{100} =\frac{410}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$82y=100(410)\\82y=41000$

I now solve for y by dividing by 82.

$\frac{82y}{82} =\frac{41000}{82} \\y= $500$

The original price was $500.

5 0

3 years ago

The product 3/4 times 1/2 will be less than or greater than 3/4

Komok [63]

Answer:

less

Step-by-step explanation:

first you would multiply and get 4/8, which simplifies to 1/2, which would be 2/4, which is less than 3/4

3 0

3 years ago

Read 2 more answers

Solve 8[7-(6x-6)]+6x=0

bazaltina [42]

8[7 - (6x - 6)] + 6x = 0

8[7 - 6x + 6] + 6x = 0

56 - 48x + 48 + 6x = 0

104 - 42x = 0 .

- 42x = - 104 .

x = 52 / 21

x ≈ 2.476

5 0

3 years ago

Read 2 more answers