Ask question

Ask question

All categories

3 years ago

11

If adult grey whales weigh an average of 50 - 55 tons, about how many pounds does an adult grey whale weigh? (A ton equals 2000

pounds.)

2 answers:

LUCKY_DIMON [66]3 years ago

7 0

Answer:

100000

Step-by-step explanation:

First multiplt the given njmber with 2000 and subrat total number givem

Lostsunrise [7]3 years ago

3 0

Answer: c

Step-by-step explanation:

You might be interested in

What is the volume of a cylinder? Give an informal argument for the formula.

N76 [4]

The formula to find the volume of a cylinder is 3.14 • r squared • h

3 0

3 years ago

Please help i really need this

lorasvet [3.4K]

Answer:

ok put me brainliest please

its 215$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can anyone explain this to me??

finlep [7]

It is the first option. DF = DE. It is referring to the lengths of each line, DE and DF look like they are the same. It is not a scalene triangle it is a right triangle. EF is way too long to be equal to DE or DF

3 0

3 years ago

How can 2/3 + 3/12 be rewritten so they can be added?

Drupady [299]

well, you can multiply the values to where they are equivalent, so multiply 2/3 by 4 ( both numbers ) so you get 8/12 and 3/12, so, just in case you want POST added, the answer to 2/3 ( 8/12 ) + 3/12 = is 11/12!

Hope this helps, if not, comment below please!!!

6 0

3 years ago

Read 2 more answers

An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an

igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

$P(e_1)=0.90*0.67=0.603$

2) Left knee unsuccessful and right knee successful (X=1).

$P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067$

3) Right knee unsuccessful and left knee successful (X=1).

$P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297$

4) Both surgeries are unsuccessful (X=0).

$P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033$

Then, the mean can be calculated as the expected value:

$M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57$

The variance can be calculated as:

$V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111$

3 0

3 years ago