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Reptile [31]
3 years ago
10

Suppose that an object moves along the y-axis so that its location is y=x2+3x at time x. (Here y is in meters and x is in second

s.)
a. Find the average velocity (the average rate of change of y with respect to x) for x changing from 3 to 7.
b. Find the average velocity for xx changing from 66 to 6+h6+h seconds.
c. Find the instantaneous velocity at x=6x=6 seconds (include units help (units)).
Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

a) 13 m/s

b) (15  + h) m/s

c) 15 m/s

Step-by-step explanation:

if the location is

y=x²+3*x

then the average velocity from 3 to 7 is

Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s

then the average velocity from x=6 to to x=6+h

Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s

the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then

when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s

then v= 15 m/s

also can be found taking the derivative of y in x=6

v=dy/dx=2*x+3

for x=6

v=dy/dx=2*6+3 = 12+3=15 m/s

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What is the slope of the line passing through the point(2,-1) and the origin.
tiny-mole [99]

Answer:

- 1/2

Step-by-step explanation:

(0,0) (2,-1)

m = difference of y/difference of x = (-1 - 0) / (2 - 0) = - 1/2

y = - 1/2 x

7 0
3 years ago
Susan designed a circular pool with a diameter of 25 meters. What is the area of the bottom of the pool? Round to the nearest te
ludmilkaskok [199]
Given:
circular pool with a diameter of 25 meters.

find: area of the bottom of the pool.

It is safe to assume that the diameter of the pool is the same from the top of the pool to the bottom of the pool.

Area of a circle = π r²
where: 
π = 3.14
r = diameter / 2 = 25 meters / 2= 12.5 meters

Area of a circle = 3.14 * (12.5m)²
                        = 3.14 * 156.25 m²
Area of a circle = 490.625 m²

490.625 m² round to the nearest tenth is 490.60 m²

We round down because the number after 6 is 2. Whenever a number to be rounded off is followed by 0,1,2,3,and 4. Then, the number is rounded down.
6 0
4 years ago
What is the solution to 6x^2 + 2x + 4 = 0?
Angelina_Jolie [31]

Step 1) Divide 6 and 4 (the last 2 numbers) and bring everything else down

<em>6x^24x+2x+4</em>

Step 2) Place in parentheses

<em>(6x^24x)+(2x+4)</em>

Step 3) Figure out what you can take out of each parentheses.

**In the first one, you can take out 6x because both numbers have x and 6 is the largest number 6 and 24 can go into.**

**In the second one, you can only take out 2 because 2 is the largest number that goes into 2 and 4.**

Step 4) You will know you did it correctly when the parentheses match up

<em>6x(x+4) + 2(x+4)</em> <<< this is how it should look

Answer: <em>(6x+2)(x+4)</em>

8 0
3 years ago
I really need help with this one it's due today!!
baherus [9]

Answer:

-2/3

3/2

Step-by-step explanation:

So to have a line parallel the equation is: m1 = m2, meaning the slope (represented by m in this equation) is equal. So in the equation. 3y = - 2x + 4 you need to simplify the equation by dividing both sides by 3. Which would be like so: y = - 2/3x + 4/3, which the slope will be -2/3.

To be perpindicular you need the slope to be: m1 * m2 = - 1. So because we already know that the slope is -2/3, all we need to do is set up an equation: -2/3 * y = - 1

-2/3y = - 1

multiply both sides by 3/-2

y = 3/2

4 0
3 years ago
Set F1 = 5N at 0 degrees, F2= 5N at 90 degrees, F3 = 5N at 270 degrees and run the simulation. Using trigonometry, what net forc
Mrac [35]

Answer: find the solution in the explanation

Step-by-step explanation:

Let's use resolution of forces by resolving into x - component and y- component.

X - component.

Sum of forces = F1 - F3 - F4cos 15

Sum of forces = 0

5 - 5 - 0.97F4 = 0

- 0.97 F4 = 0

F4 = 0

Y - component

Sum of forces = F2 + F4 sin 15

Sum of forces = 0

5 + 0.26F4 = 0

0.26 F4 = -5

F4 = -5/0.26

F4 = -19.23 N

Simulating F4 back into the equation

Sum of forces = F1 - F3 - F4cos 15

- F4cos Ø = 0

- (-19.23) cos Ø = 0

Cos Ø = 0

Ø = 1

Does the angle formed approximate 15 degrees ? NO

7 0
4 years ago
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