Given the expression:
-x^2+18x-99
to solve by completing squares we proceed as follows:
-x^2+18x-99=0
this can be written as:
-x^2+18x=99
x^2-18x=-99.......i
but
c=(-b/2)²
Hence:
c=(-(-18)/2)²=81
adding 81 in both sides of i we get:
x^2-18x+81=-99+81
factorizing the quadratic we obtain:
(x-9)(x-9)=-18
thus
(x-9)²+18=0
the above takes the vertex form of :
y=(x-k)²+h
where (k,x) is the vertex:
the vertex of our expression is:
(9,18)
hence the maximum point is at (9,18)
NOTE: The vertex gives the maximum point because, from the expression we see that the coefficient of the term that has the highest degree is a negative, and since our polynomial is a quadratic expression then our graph will face down, and this will make the vertex the maximum point.
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
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Hey there i can help ya !
check the slope between the moving points
slope between (–6, –1) & (–3, 2) = 1 slope between (-3, 2) & (–1, 4) = 1 slope between (-1, 4) & (2, 7) = 1
the points are collinear and make an angle of 45 degrees with the x-axis
we can have an equation of a line passing through (-6,-1) and slope 1 as
(y + 1) = 1(x + 6) y = x + 5 is your linear model mostly
