Wow... what grade are you even in to be getting a problem like that? that's a difficult one...
Answer:
8.7 cm
Step-by-step explanation:
The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)
Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So
a^2 +b^2 = c^2
5^2 + 5^2 = c^2
25 + 25 = c^2
√50 = c
Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).
a^2 +b^2 = c^2
√50^2 + 5^2 = c^2
50 + 25 = c^2
√75 = c
c = 8.6602...
<em>when rounded to 1 d.p.</em>
c = 8.7
Line AB is 8.7 cm long.
Answer:
(-2.2, -1.6), (3, 1)
Step-by-step explanation:
You don't have to go far to find the equations. They are right there in your problem statement. Perhaps you want to find the solutions to the equations.
Use the first equation to write an expression for x, then substitute that into the second equation:
x = 2y +1
y^2 -3(2y+1)(y) +8 = 0
-5y^2 -3y +8 = 0
-(5y +8)(y -1) = 0
y = -8/5 or y = 1
The corresponding values of x are ...
x = 2(-8/5)+1 = -11/5
x = 2(1) +1 = 3
The solutions are (x, y) = (-2.2, -1.6) and (3, 1).
Answer: 377
1,400 - 1,023 = 377
1,023 + 377 = 1,400
Step-by-step explanation: easy
Answer:
7 21 35 49
3 9 18 27
Step-by-step explanation:
the top is going up by 14 and you subtract 9 from 27