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Makovka662 [10]
3 years ago
15

How to write an equation for this graph

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

y = -2/3x + 6

Step-by-step explanation:

Kind of hard to explain but...

From 0,0 go up 6, that is where the + 6 comes from in the answer

The -2/3 is because if you go down 2 (aka -2) and right 3 (aka 3) from point 0,6 you land on point 4,4

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The temperature was –3º C last night. It is now –4º C. What was the change in temperature?
allochka39001 [22]
It dropped one degree as of last night.


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4 years ago
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Determine on the argand diagram (4 + 2i) + (-2 + 3i) - (-1 + 6i)​
Nadusha1986 [10]

Answer:

4+2i-2+3i+1-6i

collect like terms

3-i

6 0
3 years ago
Winston owns a coffee cart. He charges $3.50 for a cup of coffee, and it costs him $1.50 to make each cup of coffee plus $100 a
jekas [21]

Answer:

50 cups of coffee

Step-by-step explanation:

So what you do is take 3.50 then subtract 1.50 to get the profit of one cup of coffee. ($2) Then you do the $100 and divide it by the $2 and find out how many cups of coffee he has to sell to get to the $100. (50)

6 0
3 years ago
11) Write the explicit formula
Illusion [34]

Answer:

365

Step-by-step explanation:

tn = t1 + (n - 1)(d)

t(47) = -3 + (47 - 1)(8)

t(47) = -3 + (46)(8)

t(47) = -3 + 368

t(47) = 365

6 0
3 years ago
Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

6 0
3 years ago
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