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lana66690 [7]
3 years ago
6

Can anyone help me do this please? No Links!!

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

$100,500............

Debora [2.8K]3 years ago
6 0

Solution given:

1st term[a] :$34000

common difference [d]=$3500

20 th term=?

we have

nth term=a+(n-1)th term*d

20th term=$34000+(20-1)*$3500

  • =$100500

<u>Lillian make </u><u>$100500</u><u>in her 20th year working at this job</u><u>.</u>

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Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
This question please i need help
grin007 [14]

Answer: the picture has no answer it's invalid but I will try:

X is a 90 degree angle other than that I can't do anything

Step-by-step explanation:

6 0
3 years ago
Write an answer in the form of rooted ax+b=x+c
MA_775_DIABLO [31]
Lets solve for a
ax+b=x+c
step 1:add -b to both sides
ax+b-b=c+x+-b
step 2:divide both sides
ax=-b+c+x
ax/x=-b+c+x/x
a=-b+c+x/x
answer:
a=-b+c+x/x

5 0
3 years ago
What is y=-3x written in standard form
nataly862011 [7]
This would be 3x + y = 0.

I hope this helps!
5 0
2 years ago
K-17=-12 I need help solveing this
Fed [463]
Remember, you can do ANYTHING to an equaiton as long as you do it to BOTH SIDES

we can try to get k by itself bymaking that -17 into 0 since k+0=k

-17+17=0 right so

K-17=-12
add 17 to BOTH SIDES
K+17-17=17-12
K+0=5
K=5
5 0
3 years ago
Read 2 more answers
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