First of all you have to make them equal to each other. What I mean is the following
3x+20=2x+40
Then you should just solve for x
Answer: The answer would be f^-1 (x) = x/2 - 3/2
When put in matrix form, the coefficients of
... 3x -2y = 7
... x + 4y = 2
look like
![\left[\begin{array}{cc}3&-2\\1&4\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-2%5C%5C1%264%5Cend%7Barray%7D%5Cright%5D%20%20)
The determinant is 3×4 - 1×(-2) = 14.
Answer:
The answer to your question is A = 200.96 u²
Step-by-step explanation:
Data
Radius A = 6
Radius B = 2
π = 3.14
Area = ?
Formula
Area = πr²
Process
1.- Calculate the radius of the large circle
Radius = radius of circle A + radius of circle B
Radius = 6 + 2
Radius = 8
2.- Substitute in the formula
Area = (3.14)(8)²
Area = 3.14(64)
Area = 200.96 u²