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poizon [28]
2 years ago
9

I need some help with this

Mathematics
1 answer:
sertanlavr [38]2 years ago
8 0

Answer:

B and C

Step-by-step explanation:

Im pretty sure its those two

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Bernice found that the slope of a trend line is –3 and a point on the trend line is (8, 10). She wanted to find the equation of
shusha [124]

Answer:b

Step-by-step explanation:

5 0
2 years ago
Hey can you help me fast!!
madreJ [45]
I think it’s 36 square feet
7 0
2 years ago
Line segment AB is drawn in the coordinate plane. Carlos graphed the set of points that are the same distance from both point A
Maru [420]

Answer:

Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)

Step-by-step explanation:

Carlos graphed the set of points that are equidistant from both point A and point B.

Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)

7 0
3 years ago
A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
2 years ago
A cube has a volume of 64 cubic units. What is its surface area
Alona [7]
The volume of a cube is length x width x depth. In a cube all would be equal therefore. 

<span>x^3= 64 </span>
<span>x =4 </span>
<span>The area in square feet of one side would then be length x width </span>

<span>There are 6 sides so the surface area of the cube would be </span>

<span>(4)(4)(6) = 96 square feet</span>
7 0
3 years ago
Read 2 more answers
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