Question

Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.

Answer 1

Answer: $\text{V}=7,680\ cm^3$

Step-by-step explanation:

The volume of a pyramid is given by :-

$\text{Volume}=\dfrac{1}{3}\text{base area *height}$

Given: Slant height of the pyramid (l)= 26 cm

The base edge of the pyramid (s)=48 cm

Now, the height of the pyramid is given by :

$h=\sqrt{l^2-(\dfrac{s}{2})^2}\\\\\Rightarrow\ h=\sqrt{26^2-(\dfrac{48}{2})^2}\\\\\Rightarrow\ h=10\ cm$

Now, the volume of the square pyramid is given by :-

$\text{V}=\dfrac{1}{3}(48)^2(10)\\\\\Rightarrow\ \text{V}=7680\ cm^3$

Answer 2

The volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm = 7,680cm^3