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3 years ago

14

I need help please.

1 answer:

nignag [31]3 years ago

8 0

Answer:

it might be A but dont trust me

Step-by-step explanation:

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Ariana wants to ride her bicycle 37 miles this week. She has already ridden 14 miles. If she rides for 5 more days, write and so

lakkis [162]

Answer:

4.6 miles for 5 days.

Step-by-step explanation:

37 - 14 = 23

23 divided by 5 = 4.6

7 0

3 years ago

Find the quotient and any excluded values.<br><br> (x + 5/x^2 + 9x + 20)/(x^2-16/x-4)

Wittaler [7]

By <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:

x+5
----------------------
x^2 + 9x + 20

and by

</span><span>(x^2-16/x-4)
x^2-16
you apparently meant ---------------
x - 4

Please use additional parentheses for clarity.

Dividing,

</span> x+5 (x-4)(x+4)
---------------------- * ---------------
x^2 + 9x + 20 x-4

Now, x^2 + 9x + 20 factors into (x+4)(x+5), so what we have now is

(x+5)(x+4)
------------------------- = 1 This is true for all x, so there are no exclusions.
(x+4)(x+5)

3 0

3 years ago

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Make x the subject of the formula<br>y = mx + b

zubka84 [21]

Step-by-step explanation:

y=mx+c

Take c from both sides:

y-c = mx

Divide both sides by m:

(y-c) / m =x

Now swap sides to make it prettier:

x = (y-c) / m

6 0

2 years ago

Read 2 more answers

Each side of a square calendar is 6 inches long. What is the calendar's area?

forsale [732]

The area would be 36 each side is 6 inches therefore you would multiply 6 by 6 to find the area

3 0

3 years ago

Read 2 more answers