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4 years ago

An elevator travels 310 feet in 10 seconds. At that speed, how far can't his elevator travel in 12 seconds?

Mathematics

1 answer:

mixer [17]4 years ago

7 0

It CAN travel 372 feet in 12 seconds. ( sorry if wrong )

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Find the value of x in the isosceles triangle shown below.<br> 2<br> 2<br> 12<br> 10

Rudik [331]

Answer: x=13

Step-by-step explanation:

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3 years ago

A right triangle and some of its measurements are shown in this diagram. Based on the measurements shown in the diagram, what is

Evgesh-ka [11]

Answer:

t = 6√3 mm

Step-by-step explanation:

The angles of the triangle are 30°, 60°, and 90°. That's lucky for you, because the sides of a 30°-60°-90° triangle are always in the ratio 1:√3:2

The side opposite the 90° angle is 12 mm, so the side opposite the 30° angle is 12/2 = 6 mm

t = side opposite the 60° angle = 6√3 mm.

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3 years ago

Write 9/7 as a mixed number. Give your answer in its simplest form.

HACTEHA [7]

Answer:

1 2/7 ........................................

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3 years ago

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Manuel's age is 2 years less than twice niko's age. if we let x x represent niko's age, write an algebraic expression for manuel

olga2289 [7]

let M be Manuel's age

M = 2x - 2 ( twice Niko's age less 2 )

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3 years ago

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 99.9% of people

aleksklad [387]

Answer:

Part a: The probability that someone tests positive and does not have the disease is given as P(F'|E) is 0.6667

Part b: The probability that someone tests negative and have the disease is given as P(F|E') is 0.000000103

Step-by-step explanation:

The event that the test is positive is E and the patient has disease is F

The probability of a person having disease is P(F)=1/10000=0.0001

The probability of a person having disease and test positive is P(E|F)=0.999

The probability of a person not having disease and testing positive is P(E|F')=0.0002

Now by using complement rule, the value of people not having the disease is P(F')=1-P(F)=1-0.0001=0.9999

Part a:

The probability that someone tests positive and does not have the disease is given as P(F'|E) by Bayes theorem is as

$P(F'|E)=\dfrac{P(E|F')P(F')}{P(E|F)P(F)+P(E|F')P(F')}$

By substitution of the values

$P(F'|E)=\dfrac{P(E|F')P(F')}{P(E|F)P(F)+P(E|F')P(F')}\\P(F'|E)=\dfrac{(0.0002)(0.9999)}{(0.9999)(0.0001)+(0.0002)(0.9999)}\\P(F'|E)=\dfrac{0.00019998}{0.00029997}\\P(F'|E)=0.6667$

The probability that someone tests positive and does not have the disease is given as P(F'|E) is 0.6667

Part b

The probability that someone tests positive and does not have the disease is given as P(F|E') by Bayes theorem is as

$P(F|E')=\dfrac{P(E'|F)P(F)}{P(E'|F)P(F)+P(E'|F')P(F')}$

The probabilities are calculated as

P(E'|F)=1-P(E|F)=1-0.999=0.001

P(E'|F')=1-P(E|F')=1-0.0002=0.9998

By substitution of the values

$P(F|E')=\dfrac{P(E'|F)P(F)}{P(E'|F)P(F)+P(E'|F')P(F')}\\P(F|E')=\dfrac{(0.001)(0.0001)}{(0.001)(0.0001)+(0.9998)(0.9999)}\\P(F|E')=\dfrac{0.0000001}{0.99970012}\\P(F|E')=0.000000103$

The probability that someone tests negative and have the disease is given as P(F|E') is 0.000000103

6 0

3 years ago