9514 1404 393
Answer:
4
Step-by-step explanation:
To find the value of g(7), locate 7 on the x-axis. Follow the grid line upward until it meets the graph (blue line). At that point, follow the grid line to the left until it meets the y-axis. Read the value from the scale on the y-axis.
g(7) = 4
Answer:
we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.
Step-by-step explanation:
H0 : μ = 582
H1 : μ < 582
Test statistic :
T = (xbar - μ) ÷ σ/√n
Xbar = 515 ; n = 20 ; σ = 120
T = (515 - 582) ÷ 120/√20
T = -67 / 26.832815
T = 2.50
Pvalue at t score = 2.50 ; df = 19 is 0.0187
At α = 0.0187
Pvalue > α ; Hence, we fail to reject the Null
Hence, we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.
Answer:
y = 5cos(πx/4) +11
Step-by-step explanation:
The radius is 5 ft, so that will be the multiplier of the trig function.
The car starts at the top of the wheel, so the appropriate trig function is cosine, which is 1 (its maximum value) when its argument is zero.
The period is 8 seconds, so the argument of the cosine function will be 2π(x/8) = πx/4. This changes by 2π when x changes by 8.
The centerline of the wheel is the sum of the minimum and the radius, so is 6+5 = 11 ft. This is the offset of the scaled cosine function.
Putting that all together, you get
... y = 5cos(π/4x) + 11
_____
The answer selections don't seem to consistently identify the argument of the trig function properly. We assume that π/4(x) means (πx/4), where this product is the argument of the trig function.
Answer:


Step-by-step explanation:
The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).
The slope of side AB is

The slope of side BC is

The slope of side CD is

The slope of AD is



We see that the opposite sides of the quadrilateral ABCD are equal.
Hence the quadrilateral is a parallelogram
Answer: 6.3
Step-by-step explanation
I did this today and it's easy but you have to show a lot of work well I did but you don't have to you can just circle it in