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NemiM [27]
3 years ago
5

A case of water costs $3.80. If Safeway marks up the price 10%, what is the new price of the

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

$4.18

Step-by-step explanation:

You take $3.80 and multiply by it .1 (turn 10% into a decimal by moving the decimal to the right two places).

This gives you .38

Then you add .38 to $3.80 which gives you $4.18.

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The ratio of the number of A's in the class to B's in the class was 2:5. How many people got A's if there were 40 people who got
Umnica [9.8K]

Answer:

16 students got an A

Step-by-step explanation:

Set up an equation to compare the ratio to the scores:

\frac{2}{5} = \frac{x}{40}

Cross multiply:

80 = 5x

Divide each side by 5:

x = 16

Now, check if \frac{16}{40} = \frac{2}{5}

16/8 = 2

40/8 = 5

The ratios are the same! Therefore, 16 students got an A!

Hope this helps! Feel free to contact me if you have any questions :)

7 0
3 years ago
Read 2 more answers
Suppose that E and F are two events and that N(E and F)=300 and N(E)=730. What is P(F|E)?
marin [14]

Answer:

\displaystyle\frac{30}{73}

Step-by-step explanation:

The formula of conditional probability is:

\displaystyle P(F|E)=\frac{P(E \cap F)}{P(E)}

And if we called N(U) the total number of possible outcomes, then remember by definition of probability:

\displaystyle P(E \cap F)=\frac{N(E \cap F)}{N(U)}\\\displaystyle P(E)=\frac{N(E)}{N(U)}

Then plugging them into the formula of conditional probability we get:

\displaystyle P(F|E)=\frac{\frac{N(E \cap F)}{N(U)}}{\frac{N(E)}{N(U)}}

Then we simplify and we get:

\displaystyle P(F|E)=\frac{N(E \cap F)}{N(E)}

We just plug the given info and we get:

\displaystyle P(F|E)=\frac{300}{730}=\frac{30}{70}

3 0
3 years ago
There are 6 cans in the box . there are 4 boxes how many cans in total
Paha777 [63]

24 cans in total is your answer

8 0
3 years ago
Read 2 more answers
GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
3 years ago
(ONLY TWO CAPITAL LETTERS) PLEASE ANSWER CORRECTLY!!!!!! WILL MARK BRIANLIEST!!!!!!!! URGENT
lesantik [10]

Answer:

HN congruent to NL

Step-by-step explanation:

They have a line crossing both of them, signifiying congruence.

6 0
3 years ago
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