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4 years ago

The numbers ordered greatest to least. One number is missing 582, 478, ?, 326, 201 which number could be missing

Mathematics

2 answers:

nevsk [136]4 years ago

7 0

Answer:

All numbers between 327 and 477(inclusive) could be missing

Step-by-step explanation:

The first number is 582.

The numbers are ordered from greatest to least.

It means that the first number is the greatest, the second is greater than the third, the third greater than the fourth and the fourth greater than the fifth.

582, 478, ?, 326, 201

Following this logic, all numbers between 327 and 477(inclusive) could be missing

yarga [219]4 years ago

5 0

Answer:

See explanation

Step-by-step explanation:

The numbers are ordered from greatest to least.

The numbers are: 582, 478, ?, 326, 201.

The missing number is between 478 and 326.

Therefore all the following are possible solutions.

400

420

330

458

In fact any number greater than 326 but less than 478 is correct

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AysviL [449]

The answer would be 18 square units

Step-by-step explanation:

When talking about surface area, just add up all the units that is listed in the question. - just a tip ;)

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6 0

3 years ago

For each model below write the portion of the grid that is shaded as a percent and as a fraction. EXPLAIN.

Rudik [331]

Answer:

Just find the area of each shape .fir the first triangle it will be (0.5 x6 x6) so the answer is 18 . So the shaded part is 18 out of 100 or 18% . And so on for the trapezoid and the combined figure of square and triangle together

Step-by-step explanation:

5 0

3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

3 years ago

Classify the real number ? Help

Law Incorporation [45]

Answer:

It is an irrational number because $\pi$ is irrational

8 0

3 years ago

find the length of each isosceles right triangle when the hypotenuse of the given measure given 5 to the square root of 6

iragen [17]

In isosceles right triangle, legs are equal. Let each leg is of x units . And the given hypotenuse is 5 square 6. We use pythagorean identity here, which is

$a^2 + b^2 = c^2$

Where a=b=x and c= 5 square root 6

$x^2 +x^2 =(5 \sqrt6)^2$

$2x^2 = 150$

$x^2 =75$

$x= 5 \sqrt 3$

And that's the length of both the legs . ANd that's the required answer .

8 0

3 years ago