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Aleks04 [339]
3 years ago
13

The ratio of the number of A's in the class to B's in the class was 2:5. How many people got A's if there were 40 people who got

B's?
Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

16 students got an A

Step-by-step explanation:

Set up an equation to compare the ratio to the scores:

\frac{2}{5} = \frac{x}{40}

Cross multiply:

80 = 5x

Divide each side by 5:

x = 16

Now, check if \frac{16}{40} = \frac{2}{5}

16/8 = 2

40/8 = 5

The ratios are the same! Therefore, 16 students got an A!

Hope this helps! Feel free to contact me if you have any questions :)

oksano4ka [1.4K]3 years ago
3 0

Total- no- of- students = 56\\A -students = Total- no- of- students - B-students\\A - students = 56 - 40\\A students = 16Answer:

A Students = 16 students

Step-by-step explanation:

A :B\\2 :5\\ No- of -A -students =?\\No- of -B -students = 40\\2+5 =7\\\frac{5}{7} *x = 40\\\frac{5x}{7} =40\\Cross - multiply\\280 = 5x\\Divide-both-sides-of-the-equation -by 5\\\\\frac{280}{5}  =   \frac{5x}{5} \\x = 56

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the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of
NeX [460]
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)







8 0
3 years ago
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Sam and Paul started a business. Their investments were in the ratio 6 : 7, respectively. How much did Paul invest if Sam's inve
salantis [7]

Answer:

$966

Step-by-step explanation:

6/7 =  828/x

Write a proportion.

6x = 7(828) Use cross products.

6x = 5796 Multiply.

x = 966 Divide both sides by 6.

Paul's investment was $966.

4 0
2 years ago
Compare. Use >, <, or = to complete the statement. | –10 | | 11 | A. > B. = C. <
mash [69]
Answer: |-10| < |11|

So choice C. is right.

hope this helps!
6 0
3 years ago
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Find the solution set of the following quadratic equations using the quadratic formula.
oksian1 [2.3K]

Answer:

<h3>                1)  x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2</h3><h3>                2)   x_1=-\dfrac13\,,\quad x_2=-3    </h3>

Step-by-step explanation:

<h3>1)</h3>

x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2

<h3>2)</h3><h3>3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3</h3>
7 0
3 years ago
Least to greatest -.6 -5/8 -7/12 -.72
svlad2 [7]

It would be:

-.72 < -5/8 < -.6 < -7/12


4 0
3 years ago
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