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Aleks04 [339]
4 years ago
13

The ratio of the number of A's in the class to B's in the class was 2:5. How many people got A's if there were 40 people who got

B's?
Mathematics
2 answers:
Umnica [9.8K]4 years ago
7 0

Answer:

16 students got an A

Step-by-step explanation:

Set up an equation to compare the ratio to the scores:

\frac{2}{5} = \frac{x}{40}

Cross multiply:

80 = 5x

Divide each side by 5:

x = 16

Now, check if \frac{16}{40} = \frac{2}{5}

16/8 = 2

40/8 = 5

The ratios are the same! Therefore, 16 students got an A!

Hope this helps! Feel free to contact me if you have any questions :)

oksano4ka [1.4K]4 years ago
3 0

Total- no- of- students = 56\\A -students = Total- no- of- students - B-students\\A - students = 56 - 40\\A students = 16Answer:

A Students = 16 students

Step-by-step explanation:

A :B\\2 :5\\ No- of -A -students =?\\No- of -B -students = 40\\2+5 =7\\\frac{5}{7} *x = 40\\\frac{5x}{7} =40\\Cross - multiply\\280 = 5x\\Divide-both-sides-of-the-equation -by 5\\\\\frac{280}{5}  =   \frac{5x}{5} \\x = 56

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KLMN - parallelogram LF ⊥ KN , LD ⊥ NM m∠FLD = 35° Find: Angles of KLMN
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The question is four parts, It is required the angles of <span>parallelogram KLMN
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</span>So, It is required ⇒ ∠K  , ∠L  , ∠M  and ∠N
See the attached figure which represents the explanation of the problem
========================
Part (1): Find  ∠N:
==============
in the shape FLDN
<span>∵ LF ⊥ KN  ⇒⇒⇒ ∴ ∠LFN = 90°</span><span>
</span>∵ <span>LD ⊥ NM ⇒⇒⇒ ∴ ∠LDN = 90°</span><span>
</span>∵ The sum of all angels of FLDN = 360°
∵ <span>∠FLD = 35°</span><span>
</span>∴ ∠FLD + <span>∠LDN + ∠DNF + </span><span>∠LFN = 360°</span><span>
</span>∴ 35° + 90° + <span>∠DNF + 90° = 360°</span><span>
</span>∴ ∠DNF = 360° - ( 90° + 90° + 35°) = 360° - 215<span>° = 145°
</span>
∴ The measure of angle N = 145°
=============================
Part (2): Find  ∠M:
==============
∵ KLMN is <span>parallelogram , ∠N = 145°</span>
∴ The angles N and M are supplementary angles ⇒ property of the parallelogram
∴ ∠M + ∠N = 180°
∴ ∠M = 180° - ∠N = 180° - 145° = 35°

∴ The measure of angle M = 35°

================================

Part (3): Find  ∠L:
==============
∵ KLMN is parallelogram , ∠M = 35°
∴ The angles N and M are supplementary angles ⇒ property of the parallelogram
∴ ∠M + ∠KLM = 180°
∴ ∠KLM = 180° - ∠M = 180° - 35° = 145°
OR ∠KLM = ∠N = 145° ⇒⇒⇒  property of the parallelogram

∴ The measure of angle KLM = 145°
===================================

Part (4): Find  ∠K:
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∴ The angles N and M are supplementary angles ⇒ property of the parallelogram
∴ ∠K + ∠N = 180°
∴ ∠K = 180° - ∠N = 180° - 145° = 35°
OR ∠K = ∠M = 35° ⇒⇒⇒  property of the parallelogram

∴ The measure of angle K = 35°

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