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Lemur [1.5K]
2 years ago
5

Which points are reflections of each other across both axes? (-2, 8)and(2, -8) (-7, -1)and(-7, 1) (5, -6)and(-5, -6) (4, -3)and

(-3, 4)
Mathematics
2 answers:
dimulka [17.4K]2 years ago
8 0
7 )-(6(5)—=q1278r(4)g
Butoxors [25]2 years ago
4 0
(-2,8) and (2,-8) if you put it on the chart both points should be reflecting each other across (0,0) which is both axes
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2 5x2 - 19x + 12<br> Standard form
irina [24]

Answer:

5x 2 19x 4

9 6x 2 19x 2

factor 5x 2 19x 4

4x 2 19x 5 0

factor 6x 2 19x 7

6x 2 19x 36Factor 5x^2-19x+12. For a polynomial of the form , rewrite the middle term as a sum of two terms whose product is and whose sum is . Tap for more steps... Factor out of . Rewrite as plus. Apply the distributive property. Factor out the greatest common factor from each group. Tap for more steps...

Step-by-step explanation:

5 0
2 years ago
Is the circumference of all circles about 3 times greater than their diameters. and why?
stira [4]

Answer:

<h2>Yes the circumference is about times greater than their diameters</h2>

Step-by-step explanation:

We will approach this problem by doing a check

Say the diameter of a circle is 4 cm

Hence the radius is 3 cm

We know that the circumference is C=2\pi r

C=2*3.142*2= 12.57cm

The circumference is about 3 time bigger than the diameter

Let us try another case say the diameter is 6 cm

The radius is 3 cm

C=2*3.142*3= 18.85cm

8 0
3 years ago
the diameter of the sweep of the main rotor of the eh101 helicopter is 18.6 meters. A toy model of it has a sweep of 31 centimet
Aliun [14]

Answer:

The actual length of 60 cm is modeled as 1 cm length.

Step-by-step explanation:

The diameter of the sweep of the main rotor of the helicopter is 18.6 meters i.e. 1860 cm.

Now, the toy model of the helicopter has a sweep of 31 cm.

Therefore, the scale in which the model is made is 1860 : 31 i.e. 60 : 1 ratio.

So, the actual length of 60 cm is modeled as 1 cm length. (Answer)

4 0
3 years ago
Read 2 more answers
Select the correct answer.<br> Which of the following sets of ordered pairs represents a function?
iogann1982 [59]

Answer: {(-8, -14), (-7,-12), (-6,-10), (-5,-8)}

Step-by-step explanation: A function is a relation in which each x-coordinate corresponds to exactly one y-coordinate.

In the relations show here, notice that the first set

of ordered pairs is the only set where each x-coordinate

appears once with a different y-coordinate.

In the other ordered pairs, there is an x-coordinate that appears more

than once and it corresponds to a different y-coordinate.

For example, in the second relation,

the x-coordinate -9 appears twice.

In one case, -9 corresponds to -12 and

in the other case, it corresponds to -8.

So, this is not a function.

3 0
3 years ago
In a given year, the average annual salary of a NFL football player was $189,000 with a standard deviation of $20,500. If a samp
nika2105 [10]

Answer:

15.15% probability that the sample mean will be $192,000 or more.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 189000, \sigma = 20500, n = 50, s = \frac{20500}{\sqrt{50}} = 2899.14

The probability that the sample mean will be $192,000 or more is

This is 1 subtracted by the pvalue of z when X = 192000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{192000 - 189000}{2899.14}

Z = 1.03

Z = 1.03 has a pvalue of 0.8485.

1-0.8485 = 0.1515

15.15% probability that the sample mean will be $192,000 or more.

7 0
3 years ago
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