The end behaviour as x gets larger and positive ( right- hand end )or larger and negative ( left- hand end )is determined by the term of the greatest degree.

For p(x) that is 4 $x^{8}$ , with

• Even degree (8) and positive leading coefficient (4), then

as x → ∞ , p(x) → ∞ and

as x → - ∞ , p(x) → ∞

5 0

3 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20" id="TexFormula1" title=" y =

MAXImum [283]

Answer:

$\displaystyle y'(27) = \frac{1}{27}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

y = ∛x

x = 27

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{3}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{3}x^{\frac{1}{3} - 1}$
Simplify: $\displaystyle y' = \frac{1}{3}x^{-\frac{2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{3x^{\frac{2}{3}}}$

Step 3: Solve

Substitute in x [Derivative]: $\displaystyle y'(27) = \frac{1}{3(27)^{\frac{2}{3}}}$
Evaluate exponents: $\displaystyle y'(27) = \frac{1}{3(9)}$
Multiply: $\displaystyle y'(27) = \frac{1}{27}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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3 years ago