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OLga [1]
3 years ago
11

HELP PLEASEE i need it

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

<u><em>1st photo:</em></u>

x = \sqrt{15}

\frac{x}{5} = \frac{3}{x}

x^{2} = 15

x = \sqrt{15}

<u><em>2nd photo:</em></u>

(a) GEH ~ FGH ~ FEG

<em>similar triangles, use similar corners in the right order</em>

(b) \frac{FE}{GE} = \frac{GE}{EH}   AND    \frac{FH}{GH} = \frac{GH}{HE}

<em>similar triangles, use similar sides in proportion</em>

<em />

<u><em>3rd photo:</em></u>

x = 4.5 or 4 1/2

\frac{x}{3} = \frac{3}{2}

<em>2x = 9</em>

<em>x = 4.5 or 4 1/2</em>

<em />

<u><em>4th photo:</em></u>

Length of string = 118.2 ft

<em>sin(40) = 76/x</em>

<em>x = 76/sin(40) = 118.2</em>

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Step-by-step explanation:

Cost of one child ticket = $1.75

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Let,

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According to given statement;

x+y=613    Eqn 1

1.75x+2.25y=1184.75    Eqn 2

Multiplying Eqn 1 by 1.75

1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00

Dividing both sides by 0.50

\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224

Putting y=224 in Eqn 1

x+224=613\\x=613-224\\x=389\\

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/11236033
  • brainly.com/question/11306893

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The plane must descend at an angle of 7.25319°.

Step-by-step explanation:

Step 1; The plane is 44km away from the control tower and is flying at a height of 5.6 km. So a right-angled triangle can be formed using these measurements. The triangle's adjacent side measures 44 kilometers while the opposite side measures 5.6 kilometers. We need to find the angle of the triangle.

Step 2; Since we have the length of the opposite side and the length of the adjacent side we can determine the tan of any unknown angle. Assume the angle of the triangle is x°.

tan x° = \frac{opposite side}{adjacent side} = \frac{5.6}{44} = 0.127272, x° = tan^{-1} (0.127272) = 7.25319°.

So the plane's angle of descent must be 7.25319° to land near the control tower.

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