Answer:
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Step-by-step explanation:
second order reaction: The rate of reaction proportional to the square of the concentration of reactant.
For second order reaction

K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹
a = initial concentration of reactant = 2.30 M
a-x = concentration of reactant after t h
t = time = 4.5 h
Putting the values in the above equation,





Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
00 x 0.24 = a x 0.40 + ( 700 -a ) x 0.15 = 0.40 a - 0.15 a + 105.00
<span>168.00 = 0.25a + 105.00 </span>
<span>a = 252 </span>
<span>Solution with 40% ....................252 liters........................ans </span>
<span>Solution with 15 % ...................700 - 252= 448 liters.........................ans</span>
Answer:
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Step-by-step explanation:
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