The answer is D. Species A will have fewer phenotypes.
Alleles are alternative forms of a gene. In species A, the leaf color is controlled by two alleles, for example, P and Q. They will have three possible genotypes - PP, PQ, and QQ. Three different genotypes give maximum three phenotypes.In species B, leaf color is controlled by three alleles, for example, L, M, and N. They will have six different genotypes - LL, LM, LN, MM, MN, and NN. Six different genotypes give maximum 6 phenotypes.
Animal cells communicate via their extracellular matrices and are connected to each other via tight junctions, desmosomes, and gap junctions
Answer:
the shape
Explanation:
If it’s round it would be animal and if it’s square-like it would be plant cell. Hope this helps!
It is always beneficial to study the diseases of other animals because many of these diseases can be transmitted to humans as well. It's also essential in order to save the lives of dogs.
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
