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4 years ago

The difference of 10 and u

Mathematics

1 answer:

Vika [28.1K]4 years ago

7 0

Difference=subtraction 10-u

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Mark wants to sell his condo. Jack and Nick are two prospective buyers. Jack is willing to pay the amount quoted by Mark, while

Nadya [2.5K]

The answer is C
it is definitely c it is the only thing that makes sense.

5 0

3 years ago

1. A box without a top is to be made from a rectangular piece of cardboard, with dimensions 3 in. b)

Soloha48 [4]

Answer:

a) The volume of the box is represented by $V = 21\cdot x - 20\cdot x^{2}+4\cdot x^{3}$ .

b) A side length of 0.653 inches leads to the maximum volume of the box: 6.299 inches.

Step-by-step explanation:

a) The volume of the box ( $V$ ), in cubic inches, is modelled by the equation for the cuboid:

$V = (3-2\cdot x) \cdot (7-2\cdot x) \cdot x$ (1)

Where $x$ is the side length of the cutted square corners, in inches.

$V = (21 - 20\cdot x + 4\cdot x^{2})\cdot x$

$V = 21\cdot x - 20\cdot x^{2}+4\cdot x^{3}$

The volume of the box is represented by $V = 21\cdot x - 20\cdot x^{2}+4\cdot x^{3}$ .

b) The method consist in graphing the polynomial and looking for a relative maximum. We graph the equation found in a) by means of a graphic tool. We present the outcome in the image attached below. According to this, a side length of 0.653 inches leads to the maximum volume of the box: 6.299 inches.

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3 years ago

1. Set G is the set of positive integers divisible by 4 and set F is the set of perfect squares. List thr first 5 elements of se

Readme [11.4K]

Answer:

Step-by-step explanation:

= 200 +142 -28

=342-28

=314

= 1000

3 0

3 years ago

Quick help 1/2x+3<2x-6

Ad libitum [116K]

Answer:

x>6

*math work*

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3 years ago

1. Find the vertices and locate the foci for the hyperbola whose equation is given.

Irina18 [472]

$\bf \cfrac{(x-{{ h}})^2}{{{ a}}^2}-\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1
\qquad center\ ({{ h}},{{ k}})\qquad
 vertices\ ({{ h}}\pm a, {{ k}})\\\\
-----------------------------\\\\
\textit{now let's take a look at yours}
\\\\\\
49x2 - 16y2 = 784\implies \cfrac{49x^2}{784}-\cfrac{16y^2}{784}=1
\\\\\\
\cfrac{x^2}{16}-\cfrac{y^2}{49}=1\implies \cfrac{(x-0)^2}{4^2}-\cfrac{(y-0)^2}{7^2}=1
\\\\\\
recall\implies center\ ({{ h}},{{ k}})\qquad vertices\ ({{ h}}\pm a, {{ k}})
\\\\\\
$

$\bf \textit{now, for the foci, the foci are "c" distance from the center point}\\\\\
whereas\qquad c=\sqrt{a^2+b^2}\qquad \textit{ that is }\qquad h\pm \sqrt{a^2+b^2}$

notice your "a" and "b" components, to get the distance "c" from the center to either foci and the vertices, of course, are h + a, k and h - a, k

5 0

3 years ago