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inna [77]
2 years ago
8

A baseball team won 16 of 24 games in the first season in several seasons combined and they won 36 games. How many games did the

y play in the combined seasons?​
Mathematics
1 answer:
Elodia [21]2 years ago
5 0

Answer:

54

Step-by-step explanation:

16 is 2/3 of 24

36 is 2/3 of 54

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A triangle has three sides 35cm 54 cm and 61 cm find its area Also find the smallest of its altitude ​
I am Lyosha [343]

Answer:

Area of given triangle is 939.15cm² and smallest altitude is 30.8cm

<h3>Solution:</h3>

We are given three sides of a triangle, Let the sides be :

  • ( a ) = 35 cm

  • ( b ) = 54 cm

  • ( c ) = 61 cm

We can find the area of the triangle with its three sides using Heron's Formula

  • <u>Heron's </u><u>Formula</u>

Heron's formula was founded by hero of Alexandria, for finding the area of triangle in terms of the length of its sides. Heron's formula can be written as:

\sf{   \pmb { \longrightarrow \:  \sqrt{s(s - a)(s - b)(s - c)} }}

where ( s ) :

\sf \longrightarrow s = \dfrac{a + b + c}{2}

Therefore, for the given triangle first we will calculate ( s )

\begin {aligned}\quad & \quad \longmapsto  \sf  s =  \dfrac{a + b + c}{2}  \\  & \quad \longmapsto  \sf s =  \dfrac{35 + 54 + 61}{2}  \\ & \quad \longmapsto  \sf s =  \dfrac{150}{2}  \\ & \quad \longmapsto  \sf s  = 75cm \end{aligned}

Now, Area of triangle will be:

\begin{aligned}&:\implies \sf\quad \sf \:  A = \sqrt{s(s - a)(s - b)(s - c)} \\ &:\implies \sf\quad \sf \:  A = \sqrt{75(75 - 35)(75 - 54)(75 - 61)}   \\&:\implies \sf\quad \sf \:  A = \sqrt{75 \times 40 \times 21 \times 14}  \\ &:\implies \sf\quad \sf \:  A = \sqrt{5 \times 5 \times 3 \times 3 \times 2 \times 2 \times 7 \times 7 \times 2 \times 2 \times 5}  \\ &:\implies \sf\quad \sf \:  A =5 \times 3 \times 2 \times 7 \times 2 \sqrt{5}  \\ &:\implies \sf\quad \sf \:  A =420 \times 2.23 \\ &:\implies \sf\quad \sf \boxed{ \pmb{ \sf   A =939.15 {cm}^{2} }} \end{aligned}

Also, we have to find the smallest altitude, and the smallest altitude will be on the longest side. So,

\begin{aligned}&:\implies \sf\quad \sf \:  Area =939.15 \\ &:\implies \sf\quad \sf \:   \dfrac{1}{2}  \times b \times h =939.15 \\ &:\implies \sf\quad \sf \:   \dfrac{1}{2} \times 61 \times h  = 939.15 \\&:\implies \sf\quad \sf \:  h =939.15 \times  \dfrac{2}{61}   \\&:\implies \sf\quad \sf \:  h = \dfrac{1818.3}{61}  \\ &:\implies \sf\quad  \boxed{ \pmb{\sf \:  h =30.79 \: (approx)}} \end{aligned}

3 0
2 years ago
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Plz answer fast today
True [87]

Answer:

5 + 5 + 3 × 7

Step-by-step explanation:

Correct me if I'm wrong.

8 0
3 years ago
Find x <br> (4x - 3) – ( x + 5) = 3(10 - x)<br> please.....
Marina CMI [18]

Answer:

x=14/3

Step-by-step explanation:

4x-3-x+5=30-3x

3x+2=30-3x

3x+3x=30-2

6x=28

x=28/6=14/3

x=14/3

<em>Hope this helps</em>

<em>please mark me as brainliest.</em>

3 0
3 years ago
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HELP PLEASE!! Can someone please check if my answer is right??!!
babymother [125]

Answer:

Did you write absolute value of x -2?

5 0
3 years ago
Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate:_________.
andreyandreev [35.5K]

Answer:

B. z Subscript alpha divided by 2 zα/2 = 1.96.

Step-by-step explanation:

We are given that we want to construct a confidence interval. For this, the summary statistics for randomly selected weights of newborn​ girls:

n = 236​, \bar x = 30.3 ​hg, s = 7.2 hg. The confidence level is 95​%.

As we can clearly see here that the population standard deviation is unknown and the sample size is also very large.

It has been stated that when the population standard deviation is unknown, we should use t-distribution but since the sample size is very large so we can use z distribution also as it is stated that at very large samples; the t-distribution corresponds to the z-distribution.

Here, \alpha = level of significance = 1 - 0.95 = 0.05 or 5%

         \frac{\alpha}{2}=\frac{0.05}{2} = 0.025 or 2.5%

So, the value of Z_(_\frac{\alpha}{2} _) in the z table is given as 1.96 with a 2.5% level of significance.

3 0
3 years ago
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