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3 years ago

Please help with this question

Mathematics

2 answers:

scoray [572]3 years ago

4 0

Answer:

ΔABC is a isosceles triangle at A

=> ∠BAC = 180 - 2.∠ABC = 180 - 2.65 = 50°

because AB//CD => x = ∠BAC = 50°

Step-by-step explanation:

Firlakuza [10]3 years ago

3 0

Step-by-step explanation:

base angles of isosceles triangle is always equal.

the sum of 3 angles of a triangle is 180'

the alternate angles in a parallel line are equal to each other.

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Charra [1.4K]

Since 1*7=7, 1 4/7= (7+4)/7=11/7. When dividing fractions, we switch the numerator and denominator for the bottom number, so in this case we'd have
(11/7)*(6/5)=66/35=around 1.89

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3 years ago

A lot measuring 240 ft by 400 ft is selling for $400 a front foot. what is the price

Elena-2011 [213]

A lot measuring 240' by 400' is selling for $400 a front foot. What is the price? a) $1,600 b) $16,000 c) $72,000

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3 years ago

The graphs below have the same shape. What is the equation of the blue graph.

iragen [17]

Answer:

C) G(x) = (x-1)³

Step-by-step explanation:

The blue graph has been shifted 1 unit to the right of the red graph.

When a function is transformed by shifting horizontally, a number has either been added or subtracted from x before the exponent is applied. Since it is shifted to the right, this means 1 unit has been subtracted from x; this makes it

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3 years ago

Read 2 more answers

Y=x.arctan(x)^1/2. find dy/dx. pls show steps

Whitepunk [10]

$y=x(\arctan x)^{1/2}$

Use the product rule first:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

Use the chain rule to compute the derivative of $(\arctan x)^{1/2}$ . Let $z=(\arctan x)^{1/2}$ and take $u=\arctan x$ , so that by the chain rule

$\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}$

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}$

$\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}$

So we have

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}$

You can rewrite this a bit by factoring $(\arctan x)^{-1/2}$ , just to make it look neater:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)$

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3 years ago

Which is not equivalent to 3/5

Valentin [98]

Answer: d.

15/24 is not an equivalent fraction of 3/5.

8 0

3 years ago

Please help with this question ​

Please help with this question