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bezimeni [28]
3 years ago
8

Find the missing lengths in the triangle. round to the nearest tenth if necessary

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0

Answer:

x=8,\\y\approx 6.9

Step-by-step explanation:

The side lengths of all 30-60-90 triangles are in ratio x:x\sqrt{3}:2x}, where 2x is the hypotenuse of the triangle and x is the side opposite to the 30 degree angle.

In the given diagram, the side labelled 4 is opposite to the 30 degree angle. Since x is labelled as the hypotenuse of the triangle, x must be 4\cdot 2=\boxed{8}.

Variable y must then represent x\sqrt{3} for x=4, yielding y=4\sqrt{3}\approx \boxed{6.9}

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AB 1 CD. Find x.<br> 4x + 50
yKpoI14uk [10]

Answer:

4x +50=90

X=(90-50):4

X=10

8 0
3 years ago
Find the area of the following ellipse. a = 4.5 m; b = 5.5 m
LenaWriter [7]

Answer:

Area of ellipse is ≈ 77.78 m^{2}

Step-by-step explanation:

Given the dimension of ellipse

  a = 4.5 m

  b = 5.5 m

Now, Area of ellipse = \pi ab

                                  = \frac{22}{7}\times 4.5\times 5.5

                                  = \frac{5445}{70}

                                  = 77.78 m^{2}

Hence Area of ellipse will be 77.78 m^{2}

6 0
3 years ago
Read 2 more answers
Does a statistics course improve a student's mathematics skills,as measured by a national test? Suppose a random sample of 13 st
viva [34]

Answer:

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

P-value=0.042.

Step-by-step explanation:

The question is incomplete:

The data of the scores for each student is:

Before    After

430        465

485        475

520        535

360        410

440        425

500        505

425        450

470        480

515        520

430        430

450        460

495        500

540        530

We will generate a sample for the difference of scores (before - after) and test that sample.

The sample of the difference is [35 -10 15 50 -15 5 25 10 5 0 10 5 -10]

This sample, of size n=13, has a mean of 9.615 and a standard deviation of 18.423.

The claim is that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

Then, the null and alternative hypothesis are:

H_0: \mu=0\\\\H_a:\mu> 0

The significance level is 0.01.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{18.423}{\sqrt{13}}=5.11

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{9.615-0}{5.11}=\dfrac{9.615}{5.11}=1.882

The degrees of freedom for this sample size are:

df=n-1=13-1=12

This test is a right-tailed test, with 12 degrees of freedom and t=1.882, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>1.882)=0.042

As the P-value (0.042) is bigger than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the scores after the stats course are significantly higher than the scores before (the difference in the scores is higher than 0).

4 0
3 years ago
Simplify the expression. (4 − 4i)(−2 + 5i)
swat32
12 + 28i
is your answer
6 0
3 years ago
Read 2 more answers
What is the slope of the line that goes through<br> (2,-2) and (-1, 1)?
Olegator [25]

Answer:

m = -1

Step-by-step explanation:

use the slope formula so m = 1- -2 / -1 - 2

m = 1+2/-3, m=3/-3 so m = -1

6 0
3 years ago
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